[英]Converting Sql query to CodeIgniter Active Records
I wanted to query only those items that have a highest likes. 我想只查询那些喜欢最高的项目。
This is the sql query I want to convert into CodeIgnitor's Active Records: 这是我要转换为CodeIgnitor的Active Records的SQL查询:
SELECT *, SUM(like) as totalLikes
FROM tbl_like
GROUP BY uploadID
ORDER BY totalLikes DESC
LIMIT 2
CodeIgniter: 笨:
public function get_cheezyPic(){
$this->db->select('uploadID, SUM(like) as totalLikes');
$this->db->from('tbl_like');
$this->db->group_by('uploadID');
$this->db->order_by('totalLikes DESC');
$this->db->limit(2);
$query= $this->db->get();
return $query->result_array();}
But when I try to run this code, I've got this error 但是当我尝试运行此代码时,我遇到了这个错误
You have an error in your SQL syntax; 您的SQL语法有错误; check the manual that corresponds to your MySQL server version for the right syntax to use near 'like) as totalLikes FROM (
tbl_like
) GROUP BYuploadID
ORDER BYtotalLikes
' at line 1 查看与您的MySQL服务器版本对应的手册,以便在'like)附近使用正确的语法作为totalLikes FROM(tbl_like
)GROUP BYuploadID
ORDER BYtotalLikes
'在第1行
SELECT `uploadID`, SUM(like) as totalLikes FROM (`tbl_like`) GROUP BY `uploadID` ORDER BY `totalLikes` desc LIMIT 2
What's wrong with this code? 这段代码出了什么问题?
Thanks for the help. 谢谢您的帮助。
This'll work for you. 这对你有用。 Please note that you were using reserved keyword so it should be enclosed with backtic `` . 请注意,您使用保留关键字,所以应该用backtic``包围。
public function get_cheezyPic(){
$this->db->select('uploadID, SUM(`like`) as totalLikes',false);
$this->db->from('tbl_like');
$this->db->group_by('uploadID');
$this->db->order_by('totalLikes DESC');
$this->db->limit(2);
$query= $this->db->get();
return $query->result_array();
}
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.