簡體   English   中英

將Sql查詢轉換為CodeIgniter Active Records

[英]Converting Sql query to CodeIgniter Active Records

我想只查詢那些喜歡最高的項目。

這是我要轉換為CodeIgnitor的Active Records的SQL查詢:

SELECT *, SUM(like) as totalLikes
FROM tbl_like
GROUP BY uploadID
ORDER BY totalLikes DESC
LIMIT 2

笨:

public function get_cheezyPic(){
      $this->db->select('uploadID, SUM(like) as totalLikes');
      $this->db->from('tbl_like');
      $this->db->group_by('uploadID');
      $this->db->order_by('totalLikes DESC');
      $this->db->limit(2);

      $query= $this->db->get();

      return $query->result_array();}

但是當我嘗試運行此代碼時,我遇到了這個錯誤

您的SQL語法有錯誤; 查看與您的MySQL服務器版本對應的手冊,以便在'like)附近使用正確的語法作為totalLikes FROM( tbl_like )GROUP BY uploadID ORDER BY totalLikes '在第1行

SELECT `uploadID`, SUM(like) as totalLikes FROM (`tbl_like`) GROUP BY `uploadID` ORDER BY `totalLikes` desc LIMIT 2

這段代碼出了什么問題?

謝謝您的幫助。

這對你有用。 請注意,您使用保留關鍵字,所以應該用backtic``包圍。

public function get_cheezyPic(){
      $this->db->select('uploadID, SUM(`like`) as totalLikes',false);
      $this->db->from('tbl_like');
      $this->db->group_by('uploadID');
      $this->db->order_by('totalLikes DESC');
      $this->db->limit(2);

      $query= $this->db->get();

      return $query->result_array();
}

暫無
暫無

聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.

 
粵ICP備18138465號  © 2020-2024 STACKOOM.COM