[英]Symfony2 - get main request's current route in twig partial/subrequest
In Twig partial rendered by separate controller, I want to check if current main route equals to compared route, so I can mark list item as active. 在由独立控制器呈现的Twig部分呈现中,我想检查当前主路由是否等于比较路由,因此我可以将列表项标记为活动。
How can I do that? 我怎样才能做到这一点? Trying to get current route in BarController like:
试图在BarController中获取当前路线,如:
$route = $request->get('_route');
returns null
. 返回
null
。
Uri
is also not what I'm looking for, as calling below code in bar
's twig: Uri
也不是我想要的,因为在bar
的树枝上调用下面的代码:
app.request.uri
returns route similar to: localhost/_fragment?path=path_to_bar_route
返回类似于:
localhost/_fragment?path=path_to_bar_route
路由
Full example 完整的例子
Main Controller: FooController extends Controller{ 主控制器:FooController扩展Controller {
public function fooAction(){}
}
fooAction twig: fooAction树枝:
...some stuff...
{{ render(controller('FooBundle:Bar:bar')) }}
...some stuff...
Bar controller: 酒吧控制器:
BarController extends Controller{
public function barAction(){}
}
barAction twig: barAction树枝:
<ul>
<li class="{{ (item1route == currentroute) ? 'active' : ''}}">
Item 1
</li>
<li class="{{ (item2route == currentroute) ? 'active' : ''}}">
Item 2
</li>
<li class="{{ (item3route == currentroute) ? 'active' : ''}}">
Item 3
</li>
</ul>
pabgaran 's solution should work. 帕布兰的解决方案应该有效。 However, the original problem occurs probably because of the
request_stack
. 但是,原始问题可能是因为
request_stack
。
http://symfony.com/blog/new-in-symfony-2-4-the-request-stack http://symfony.com/blog/new-in-symfony-2-4-the-request-stack
Since you are in a subrequest, you should be able to get top-level ( master
) Request
and get _route
. 由于您处于子请求中,因此您应该能够获得顶级(
master
) Request
并获取_route
。 Something like this: 像这样的东西:
public function barAction(Request $request) {
$stack = $this->get('request_stack');
$masterRequest = $stack->getMasterRequest();
$currentRoute = $masterRequest->get('_route');
...
return $this->render('Template', array('current_route' => $currentRoute );
}
Haven't run this but it should work... 没有运行它但它应该工作...
I think that the best solution in your case is past the current main route in the render: 我认为在你的情况下,最好的解决方案是通过渲染中的当前主路径:
{{ render(controller('FooBundle:Bar:bar', {'current_route' : app.request.uri})) }}
Next, return it in the response: 接下来,在响应中返回它:
public function barAction(Request $request) {
...
return $this->render('Template', array('current_route' => $request->query->get('current_route'));
}
And in your template compares with the received value. 并在您的模板中与收到的值进行比较。
Otherwise, maybe is better to use a include instead a render, if you don't need extra logic for the partial. 否则,如果你不需要额外的部分逻辑,也许最好使用include而不是render。
in twig you can send request object from main controller to sub-controller as parameter: 在twig中你可以将请求对象从主控制器发送到子控制器作为参数:
{{ render(controller('FooBundle:Bar:bar', {'request' : app.request})) }}
in sub-controller: 在子控制器中:
BarController extends Controller{
public function barAction(Request $request){
// here you can use request object as regular
$country = $request->attributes->get('route_country');
}
}
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