SQL-查找值相同或下一个最大值的所有行

Question

I have a table where in one column I have lot of Int -values from x to y and it kinda loops. The values go from lowest to highest, but start again after awhile. Values look like this:

TableRow:
2
5
10
15
..
30
40
50
// And here it begins again:
2
5
10
..
// And again:
2
5
10
// And the sequence may change too:
3
6
10

I would like to search for values that are the same, or next biggest. Ie If I have a search value of 6, I would like the search to return rows where this value is: 10, 10, 10, and so on. Not the fives, but the bigger ones. But I don't want all of the bigger ones after the value! Only the next one. If I have a search value of 1.9 or less, the search should return all the 2 -values. How do I form an sql that will accomplish this?

PS: Symfony "createQueryBuilder" -example for this would be great, but not necessary! :)

Edit: (More info) This table has other columns as well, 10 others to be exact, including id-column as well. No timestamps though.

Answer 1

You can find the value you are looking for using a subquery. Then you can get the matching rows:

select t.*
from table t
where value = (select min(value)
               from table t
               where value >= 6
              );