如何查找列的所有值都相同的行？

Question

I have a table user_test_access which stores test_id and user_id .

user_test_access table stores all the uses who have access to the test as well as which user created the test.

id	test_creator	test_id	user_id
1	0	1	901
2	0	1	903
3	0	2	904
4	0	2	905
5	0	3	906
6	1	3	907
7	0	3	908

I want a query to return all the test_id where there is no creator. ie test_creator = 0.

Desired Result:

For the particular data set the answer would be test_id 1 and 2. The reason test_id 3 is not included is because user_id 907 is the test_creator for it.

What I've tried:

SELECT test_id from user_test_access WHERE id = ALL(SELECT id from user_test_access WHERE test_creator=0) 

Can you please help me figure out what I'm doing wrong?

Answer 1

If a missing testcreator is encoded by the value 0 , you can just group by the test_id and select only ids where the sum is zero

select test_id 
from user_test_table
group by test_id
having sum(test_creator) = 0

Answer 2

You can use not exists operator as the following:

SELECT DISTINCT test_id
FROM user_test_access T
WHERE NOT EXISTS (SELECT 1 FROM user_test_access D
  WHERE D.test_id=T.test_id AND D.test_creator=1)

See a demo .