Scala类型不匹配的基础类型

Question

I'm writing methods to convert Set[Tuple2[String, String]] to String and vice versa.
I'm saving the string value as v1,v2#v3,v4#v5,v6
In order to fill the Set I'm splitting the string by ',' and in order to extract the values I'm trying to split each value by '#' but i receive

type mismatch: found: x.type (with underlying type Array[String]

The code I tried using is

val x = overwriters.split("#")
for(tuple <- x) {
  tuple.split(",")
}

The returned type of split is an array of String so it is not clear to me why i cannot split each member of the returned array

Answer 1

overwrites.split("#").map(_.split(",")).map(x=> (x(0),x(1))).toSet

这将以更加惯用的方式实现同​​样的目标。

Answer 2

tuple.split(",") returns an array of two elements. You need to convert it to a tuple.

val overwriters ="v1,v2#v3,v4#v5,v6"              
val x = overwriters.split("#").toSet
for(tuple <- x) yield {
  val t = tuple.split(",")
  (t(0),t(1))
}