data.table如何在键列上排序NA值？

Question

Using data.table, say I'm setting the key using two columns, and one of the columns has missing values. Data table seems to sort the NA values to the first values.

require(data.table)
set.seed(919)

# Create sample data
dt <- data.table(
  key1 = rep(1:10, each = 10),
  key2 = rep_len(letters, 100)
  )

# Set some key2 values to missing
dt[sample(1:100, 10), "key2"] <- NA

# Set key (sort)
setkeyv(dt, c("key1", "key2"))
dt
# 1:    1   NA
# 2:    1    a
# 3:    1    b
# 4:    1    c
# 5:    1    d
# 6:    1    f
# 7:    1    g
# 8:    1    h
# 9:    1    i
# 10:    1    j
# 11:    2   NA
# 12:    2   NA
# 13:    2    k
# 14:    2    m
# 15:    2    n
# 16:    2    o
# 17:    2    p
# 18:    2    q
# 19:    2    r
# 20:    2    s
# 21:    3    a
# 22:    3    b
# 23:    3    c
# 24:    3    d
# 25:    3    u
# 26:    3    v
# 27:    3    w
# 28:    3    x
# 29:    3    y
# 30:    3    z
# 31:    4    e
# 32:    4    f
# 33:    4    g
# 34:    4    h
# 35:    4    i
# 36:    4    j
# 37:    4    k
# 38:    4    l
# 39:    4    m
# 40:    4    n
# 41:    5   NA
# 42:    5   NA
# 43:    5    o
# 44:    5    q
# 45:    5    r
# 46:    5    s
# 47:    5    u
# 48:    5    v
# 49:    5    w
# 50:    5    x
# 51:    6   NA
# 52:    6    a
# 53:    6    b
# 54:    6    c
# 55:    6    d
# 56:    6    e
# 57:    6    g
# 58:    6    h
# 59:    6    y
# 60:    6    z
# 61:    7    i
# 62:    7    j
# 63:    7    k
# 64:    7    l
# 65:    7    m
# 66:    7    n
# 67:    7    o
# 68:    7    p
# 69:    7    q
# 70:    7    r
# 71:    8   NA
# 72:    8   NA
# 73:    8    a
# 74:    8    b
# 75:    8    t
# 76:    8    u
# 77:    8    w
# 78:    8    x
# 79:    8    y
# 80:    8    z
# 81:    9   NA
# 82:    9    c
# 83:    9    d
# 84:    9    e
# 85:    9    f
# 86:    9    h
# 87:    9    i
# 88:    9    j
# 89:    9    k
# 90:    9    l
# 91:   10   NA
# 92:   10    m
# 93:   10    n
# 94:   10    o
# 95:   10    p
# 96:   10    r
# 97:   10    s
# 98:   10    t
# 99:   10    u
# 100:   10    v
# key1 key2

Does this always happen, or will I run into problems if I always assume this is true?

Answer 1

For setkey() , data.table behaves like base R sort(x, na.last=FALSE) , as the sort order (always increasing) is essential for binary search based joins/subsets. Rationale for NA s appearing first is that:

"NAs are internally large negative number[s]" github.com/Rdatatable/data.table/issues/434

---

Miscellaneous comments: If you are just looking to reorder your data, you should consider setorder() , which is capable of sorting in any order and positioning NA s in the beginning or end.

By the way, the standard syntax there is dt[sample(1:100, 10), key2 := NA] and you should watch out for mistaking the two-character string "NA" for NA (not a problem in your example).