如何在Shell脚本中递归使用粘贴命令

Question

I have a paste command in my script. But it is not giving my desired output. my datafile is

file.txt
1
3
5
4

my shell script is

f1=file.txt
for j in 1..12
do
awk '{printf ("%.1f\n", $1+'$j');}' $f1 > $j_$f1
paste $j_$f1 > ofile.txt  # ofile.txt is a new empty file
done

This script gives output as

ofile.txt
2
4
6
5
3
5
7
6
.
.

My desired output as

ofile.txt
2  3  4  5  6 ... 13
4  5  6  7  8 ... 15
6  7  8  9  10 .. 17
5  6  7  8  9 ... 16

I also want to do for the following script

bonus_company1=10
bonus_company2=25
bonus_company3=50
declare var=("company1" "company2" "company3")
for k in var{[@]}
do for j in jan..dec
   do if [ $j == "jan" ] || [ $j == "may" ] || [ $j == "sep" ]; then
      awk '{printf ("%.1f\n", $1+ '$bonus_$k');}' $f1 > $k_$j_$f1
      elif [ $j -ne "jan" ] && [ $j -ne "may" ] && [ $j -ne "sep" ]; then
      awk '{printf ("%.1f\n", $1+5);}' $f1 > $k_$j_$f1
      fi
      paste $k_$j_$f1 > $k.txt  # $k.txt is a new empty file
   done
done

so I will get 3 different files for three companies. eg

company1.txt
11  6  6  6  11 .....
13  8  8  8  11 .....
15  10 10 10 15 .....
14  9  9  9  14 .....

Answer 1

I would suggest doing the whole thing in awk, rather than using a shell loop:

awk '{for (i=1; i<=12; ++i) printf "%d%s", $1+i, (i<12?FS:RS)}' "$f1" > output

This loop runs for each line of the file and outputs all of the columns, saving the need to use another tool such as paste . The ternary operator is used to output a space ( FS ) between each column and a newline ( RS ) at the end of the line.

---

For the second part of your question, you can still do most of the work in awk.

declare -A companies
companies=( [company1]=10 [company2]=25 [company3]=50 )
for c in "${companies[@]}"; do
    awk -v bonus="${companies[c]}" '{for (i=1; i<=12; ++i) 
        printf "%d%s", $i+(i==1||i==5||i==9?bonus:5), (i<12?FS:RS)}' "$f1" > "$c.txt"
done

I have created an associative array containing each company name and their bonus. The loop goes through each company in the array, passing the bonus to awk as a variable (note that I'm doing this using -v rather than using string concatenation). The loop goes from 1 to 12, adding the bonus for months 1, 5 and 9, or 5 otherwise. The name of the company (the key of the shell array) is used for the output file.

Answer 2

I can't understand, why are you going in such complicated way. You can do it in a more simpler way:

for 2nd one:

for k in var{[@]}
do awk '{printf("%.1f %.1f %.1f %.1f %.1f %.1f %.1f %.1f %.1f %.1f %.1f %.1f\n", $1+"$bonus_$k", $1+5, $1+5, $1+5, $1+"$bonus_$k", $1+5, $1+5, $1+5, $1+"$bonus_$k", $1+5, $1+5, $1+5);}' file.txt > $k_file.txt
done