Java条件读取文本文件

Question

I'm just wondering if there's a way to read a text file and skip a line with specific string.

For example (test1.txt):

test0,orig,valid,nice
test1,input,of,ol,[www]
test2,[eee],oa,oq
test3,wa,eee,string,int
test4,asfd,eee,[tsddas],wwww

Expected output :

test0,orig,valid,nice
test3,wa,eee,string,int

I already have this code :

String line;
String test[];

try{
    LineIterator it = FileUtils.lineIterator(file2,"UTF-8");
    while(it.hasNext()){                    
        line = it.nextLine();                    
        test = StringUtils.split(line,(",")); 
    }

Thanks in advance guys!

Answer 1

Something like:

line = it.nextLine();

if (line.contains("specific string")) continue;

test = StringUtils.split(line,(",")); 

Why are you using StringUtils to split a line? The String class supports a split(...) method.

I suggest you read the String API for basic functionality.

Answer 2

You could also make use of the Java 8 Streaming API. It allows all this rather easily.

final List<String[]> rows = Files.lines(Paths.get(file2), "UTF-8")
        .filter(l -> !l.contains("["))
        .map(l -> l.split(","))
        .collect(Collectors.toList());

If you want to do it fast and don't want to run into any issues, you should also think about using an existing CSV library. A nice example is the Apache Commons CSV library ( https://commons.apache.org/proper/commons-csv/ ).