在Shell脚本中使用SED

Question

I have two issues that I am seeking help with. I am using Cygwin and a Unix newbie.

1) I have a shell script that executes SED command. In my script called master.sh, I have the following

    sed -nrf remove.sed < code.tp4 > code.tp5

remove.sed has one line

    / INCLUDE /d

When I execute the script via the following command

bash master.sh

I get the following error

master.sh: line 12: $'\r':command not found

I have no clue on what is throwing this error.

2) My 2nd issue is that the output file "code.tp5" ends up "code.tp5?". However, using Windows explorer, the question mark appears to be unprintable characters. The most confusing part of this is that I get no errors when I execute this via the command prompt. Any assistance would be appreciated.

Answer 1

You could try:

sed -nr s/\\r//;/ INCLUDE /d' < code.tp4 > code.tp5; sed 's/$/\\r$/' code.tp5

The command 's' is for substitution. '\\r' carriage return. So s/\\r// will replace carriage return to nothing. After that you will remove the lines that contains the pattern '/ INCLUDE /d'. And with this: sed 's/$/\\r$/' code.tp5 finally you will add again the carriage return so will became again a DOS text file ( $ means end of line on a regular expression) . (Unix line endings are only new line, and DOS cas carriage return and newline).