Ajax和PHP不更新数据库

Question

This ajax code gets called, I tested it, but the database does not get updated. I think the code is small enough not to need any further explanation. When something from the class pdb gets clicked, it saves its source to the database.

$(function(){
                    $('.pdb').on('click',function(){

                        var sou = $(this).attr('src');
                        var iddo = $(this).attr('id');
                        var data = 'id='+iddo+'&value='+sou+'&turno='+(bia)?true:false;
                        $.ajax({
                             data: data,
                             type: "post",
                             url: "database.php",
                             success: function(data){
                                  alert("Prova: " + data);
                             }
                        });

                    });

                });

database.php

<?php 

        mysql_connect("localhost","pierostesting","");
        mysql_select_db("my_pierostesting");


        $id=$_POST['id'];
        $value =$_POST['value'];
        $turno=$_POST['turno'];
        if(true){

            $sql="UPDATE board SET $id=$value, turno=$turno WHERE partita=0";
            $result=mysql_query($sql);
            if($result){
                echo "Nailed it";
            }
        }else{


        }

?>

Answer 1

remove

var data = 'id='+iddo+'&value='+sou+'&turno='+bia;

and debug ajax calls use either console or firebug extension

Answer 2

replace:

var data = 'id='+iddo+'&value='+sou+'&turno='+(bia)?true:false;

with

data = { 'id':iddo,'value':sou,'turno':(bia)?true:false}

Answer 3

Needed to change the PHPto this:

$sql="UPDATE board SET $id='$value', turno=$turno WHERE partita=0";

Simply change $value with '$value', bloody ''. Thank you all guys.