[英]Linux -> Terminal command -> Grep -> Expressions / Exceptions related to symbol
Simply: I have problem with command which should print me lines containing any of those two expressions: " king" , "king's son" . 简而言之:我的命令有问题,该命令应该向我显示包含以下两个表达式之一的行:“ king” , “ king's son” 。 This is where I got so far:
这是我到目前为止的去处:
grep -w "king's son\|king" frog.txt
It does work but it include "king's" which should not happen. 它确实有效,但是它包含不应发生的“国王” 。
Adding -v grep "king's"
does not work as it deletes "king's son" also. 添加
-v grep "king's"
不起作用,因为它也会删除“ king's son” 。
I am using Ubuntu 32 bit system installed on Virtual Box Machine. 我正在使用Virtual Box Machine上安装的Ubuntu 32位系统。
-w
won't help much because king
is considered a word in king's
as '
is a non-word character. -w
也不会有多大效果,因为king
是在考虑一个字king's
为'
是一个非字字符。
Use: 采用:
grep -E "([[:space:]]|^)king('s son)?([[:space:]]|$)" frog.txt
Or using lookarounds if your grep
has PCRE option available: 或者,如果您的
grep
具有可用的PCRE选项,则使用环视方法 :
grep -P "(?<=[[:space:]]|^)king('s son)?(?=[[:space:]]|$)" frog.txt
grep -E "([[:space:]]|^)king('s son)?([[:space:]]|$)" frog.txt
For example, if frog.txt
contains 例如,如果
frog.txt
包含
kingb # no match
king's # no match
king-bee # no match
breaking # no match
king's hello # no match
king's sonth # no match
king # match
a king bee # match
king bee # match (with a TAB)
king's son # match
then the above command returns 然后上面的命令返回
king # match
a king bee # match
king bee # match (with a TAB)
king's son # match
This oughta do it: 这应该做到:
grep -E "(^|[ \t])(king|king's son)([ \t]|$)" frog.txt
It uses the groups (^|[ \\t])
and ([ \\t]|$)
to match word separators or the beginning/end of lines. 它使用组
(^|[ \\t])
和([ \\t]|$)
来匹配单词分隔符或行的开头/结尾。
grep -w "king's son\|king$" frog.txt
the following line maybe work for your situation. 以下几行可能适合您的情况。
grep -w "king's son\|king$\|king\ " frog.txt
the result is : 结果是:
king's son #match
king #match
king's hello #not match
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