如何比较忽略几个字符的两个字符串

Question

I want to compare two strings in python ignoring some characters, like if the string is:

"http://localhost:13555/ChessBoard_x16_y20.bmp"

I want to ignore the values "16" and "20" in the string; no matter what these values are, if the rest of the string is same as this string is then I should get the result "TRUE" . How can I do this?

Example:

URL = "http://localhost:13555/ChessBoard_x05_y12.bmp"

if URL == "http://localhost:13555/ChessBoard_x16_y16.bmp":
    print("TRUE")
else:
    print("FALSE")

Output:

TRUE

Answer 1

Use regular expressions . Here it is for your case. A dot matches any symbol. A \\d matches a digit. Some special symbols have to be escaped.

import re
if re.match(r'http://localhost:13555/ChessBoard_x\d\d_y\d\d\.bmp', URL):
    print("TRUE")
else:
    print("FALSE")

Answer 2

Maybe you will be able to do this with regex

>>> import re
>>> CHESS_BOARD_PATTERN = r'http://localhost:13555/ChessBoard_x\d+_y\d+.bmp'
>>> def is_chess_board_endpoint(endpoint):
...     return bool(re.match(CHESS_BOARD_PATTERN, endpoint))
... 
>>> is_chess_board_endpoint('http://localhost:13555/ChessBoard_x16_y20.bmp')
True
>>> is_chess_board_endpoint('http://localhost:13555/ChessBoard_x05_y12.bmp')
True
>>> is_chess_board_endpoint('http://google.com.br')
False

But it is obvious that depending on your solution, you have to improve this regex, because if you change the host (from localhost to 192.168.0.10 for example) will not work.

Answer 3

def checkstrings(string1, string2):
    if len(string1) != len(string2):
        return False
    for x in range(len(string1)):
        if x == 35 or x == 36 or x == 39 or x == 40:
            continue
        if string1[x] != string2[x]:
            return False
    return True

JAVA:

public static boolean checkStrings(String string1, String string2){
        if(string1.length() != string2.length()){
                return false;
        }
        for(int x = 0; x < string1.length(); x++){
                if(x == 35 || x == 36 || x == 39 || x == 40){
                        continue;
                }

                if(string1.charAt(x) != string2.charAt(x)){
                        return false;
                }
        }
        return true;

}

Answer 4

You can loop through characters in the string and check if they are digits or not. Ie

if x.isdigit():