如何在 Python 3 中比较两个字符串中的单个字符

Question

I'm trying to compare the first character of two different strings (and so on) to form a new string based on those results. This is what I've tried using, however its comparing every element of each list to each other.

def compare(a,b):
    s = ""
    for x in a:
        for y in b:
            if x == y:
                s+=str(x)
            else:
                s+=str(y)

It seems like such a simple question but I'm stuck.

Answer 1

Use zip:

def compare(a, b):
    for x, y in zip(a, b):
        if x == y:
            ...

Answer 2

Are you perhaps looking for something with logic similar to this? It chooses the alphabetically earlier character from each input string:

def compare(a,b):
    s = ""
    for i in range(len(a)):
        if a[i] < b[i]:
            s+=str(a[i])
        else:
            s+=str(b[i])
    return s

print compare ("seven", "eight")

Output:

eegen

---

The one-line version of this is

return ''.join(a[i] if a[i] < b[i] else b[i] for i in range(len(a)))

Answer 3

input(x)
input(y)
cnt = 0
 for char_val in x:
   if b[cnt] == char_val:
      print("match")
   else:
      print("mis-match")

Answer 4

Here is a complete function

def compare_strings(a,b):
    result = True
    if len(a) != len(b): print('string lengths do not match!')
    for i,(x,y) in enumerate(zip(a,b)):
        if x != y:
            print(f'char miss-match {x,y} in element {i}')
            result = False
    if result: print('strings match!')
    return result

Answer 5

def twoStrings(s1, s2):
for i in range(len(s1)):
    for j in range(len(s2)):
        if s2[j] == s1[i]:
            return 'YES'
return 'NO'

Answer 6

We can write simple and easy method to compare similar letters in two strings

def compare(a,b):
    s = ""
    t=""
    for x in a:
        for y in b:
            if x == y:
                t=x
        s=s+t
    print(s)

compare("xyz","axy")

Here first for loop will compare each letters in string and display all similar character.