[英]RDF SPARQL query multiple types
I am trying to parse a rdf graph using SPARQL. 我正在尝试使用SPARQL解析rdf图。 Naturally in a graph my entities can be more than one type at a time.
自然在图中,我的实体一次可以是一种以上的类型。
How does a SPARQL query have to look like so that I can check for both types? SPARQL查询的外观如何,以便我可以检查两种类型?
How my graph looks like: 我的图看起来如何:
<ns0:TrainArrival rdf:about="http://my.url.com/ontologies/mash-up#TrainArrival-7a60055b-1e7f-464d-b42e-b1839d623b69">
<ns0:arrivalTime rdf:datatype="&xsd;dateTime">0001-01-01T00:26:00</ns0:arrivalTime>
<ns0:description rdf:datatype="&xsd;string">Berlin - Düsseldorf - Aachen</ns0:description>
<ns0:name rdf:datatype="&xsd;string">ICE 123</ns0:name>
<ns3:primaryTopic xmlns:ns3="http://xmlns.com/foaf/0.1/" rdf:resource="http://my.url.com/ontologies/mash-up#TrainArrival-7a60055b-1e7f-464d-b42e-b1839d623b69" />
</ns0:TrainArrival>
<ns0:TrainArrival rdf:about="http://my.url.com/ontologies/mash-up#TrainArrival-88e52944-7d64-4241-bed0-61a28615e385">
<ns0:arrivalTime rdf:datatype="&xsd;dateTime">0001-01-01T00:00:00</ns0:arrivalTime>
<ns0:description rdf:datatype="&xsd;string">Duisburg - Düsseldorf - Köln - Aachen</ns0:description>
<ns0:name rdf:datatype="&xsd;string">RE 1</ns0:name>
<rdf:type rdf:resource="http://my.url.com/ontologies/mash-up#PrimaryInformation" />
<ns4:primaryTopic xmlns:ns4="http://xmlns.com/foaf/0.1/" rdf:resource="http://my.url.com/ontologies/mash-up#TrainArrival-88e52944-7d64-4241-bed0-61a28615e385" />
</ns0:TrainArrival>
The second TrainArrival has an additional type "PrimaryInformation". 第二个TrainArrival具有附加类型“ PrimaryInformation”。 How can I check if an Entity has both types, TrainArrival + PrimaryInformation?
如何检查实体是否同时具有TrainArrival和PrimaryInformation这两种类型?
My Query right now: 我现在的查询:
public String queryStringTrain =
"PREFIX rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#> "+
"PREFIX ns0: <http://my.url.com/ontologies/mash-up#> "+
"PREFIX ns1: <http://xmlns.com/foaf/0.1/> "+
"SELECT ?object ?type ?type2 ?name ?arrivalTime " +
"WHERE { " +
"?object rdf:type ?type . " +
"?object ns0:name ?name . " +
"?object ns0:arrivalTime ?arrivalTime . " +
"OPTIONAL {?object rdf:type ?type2 } " +
"}";
I then try to check like this: 然后,我尝试像这样检查:
QuerySolution soln = results.nextSolution();
String type = soln.get("type").toString();
if (soln.contains("type2")) {
String type2 = soln.getResource("type2").toString();
}
I get exceptions stating: 我得到异常说明:
com.hp.hpl.jena.rdf.model.impl.ResourceImpl cannot be cast to com.hp.hpl.jena.rdf.model.Literal
com.hp.hpl.jena.rdf.model.impl.ResourceImpl无法转换为com.hp.hpl.jena.rdf.model.Literal
What am I missing? 我想念什么? Thanks in advance!
提前致谢!
{
?object rdf:type ns0:TrainArrival ;
rdf:type ns0:PrimaryInformation ;
}
will match having both TrainArrival and PrimaryInformation 将同时拥有TrainArrival和PrimaryInformation
Based on the exception you are getting, it seems that one of the variables is not binding properly to a resource. 根据您得到的异常,似乎其中一个变量未正确绑定到资源。 I can't check this, but have you tried rewriting
String type2 = soln.getResource("type2").toString();
我无法检查,但是您是否尝试过重写
String type2 = soln.getResource("type2").toString();
to String type2 = soln.get("type2").toString();
到
String type2 = soln.get("type2").toString();
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