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Spring映射URL到控制器和视图

[英]Spring Mapping Url to Controller and View

I have the standard Spring 4.x files in Netbeans 8.0.2. 我在Netbeans 8.0.2中有标准的Spring 4.x文件。 I added a controller, RegisterController.java in the controllers -package. 我在controllers -package中添加了一个控制器RegisterController.java I also added one model, a User , with some basic information about the user. 我还添加了一个模型User ,其中包含有关该用户的一些基本信息。 Next I made 2 .jsp files, Registration.jsp and RegistrationSuccess.jsp . 接下来,我制作了2个.jsp文件Registration.jspRegistrationSuccess.jsp

Here is my RegisterController : 这是我的RegisterController

@Controller
@RequestMapping(value="/register")
public class RegisterController {
    @RequestMapping(method=RequestMethod.GET)
    public String viewRegistration(Model model){
        User user = new User();
        model.addAttribute("userForm", user);

        List<String> professionList = new ArrayList<>();
        professionList.add("Developer");
        professionList.add("Designer");
        professionList.add("IT Manager");
        model.addAttribute("professionList", professionList);

        return "Registration";
    }

    @RequestMapping(method=RequestMethod.POST)
    public String processRegistration(@ModelAttribute("userForm") User user, Map<String, Object> Model){
        System.out.println("username: " + user.getUsername());
        System.out.println("password: " + user.getPassword());
        System.out.println("email: " + user.getEmail());
        System.out.println("birth date: " + user.getBirthDate());
        System.out.println("profession: " + user.getProfession());

        return "RegistrationSuccess";
    }
}

Now, going to myProject/register results in a 404. I am confused how Spring manages the routing though. 现在,转到myProject/register结果为404。但是我很困惑Spring如何管理路由。 There is a web.xml looking like this: 有一个如下所示的web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="3.1" xmlns="http://xmlns.jcp.org/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd">
    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/applicationContext.xml</param-value>
    </context-param>
    <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener>
    <servlet>
        <servlet-name>dispatcher</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <load-on-startup>2</load-on-startup>
    </servlet>
    <servlet-mapping>
        <servlet-name>dispatcher</servlet-name>
        <url-pattern>*.htm</url-pattern>
    </servlet-mapping>
    <session-config>
        <session-timeout>
            30
        </session-timeout>
    </session-config>
    <welcome-file-list>
        <welcome-file>redirect.jsp</welcome-file>
    </welcome-file-list>
</web-app>

What I think this means is every url with *.htm goes to the dispatcher-servlet : 认为这意味着带*.htm每个URL都将进入dispatcher-servlet

<?xml version='1.0' encoding='UTF-8' ?>
<!-- was: <?xml version="1.0" encoding="UTF-8"?> -->
<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xmlns:p="http://www.springframework.org/schema/p"
       xmlns:aop="http://www.springframework.org/schema/aop"
       xmlns:tx="http://www.springframework.org/schema/tx"
       xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-4.0.xsd
       http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-4.0.xsd
       http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-4.0.xsd">

    <bean class="org.springframework.web.servlet.mvc.support.ControllerClassNameHandlerMapping"/>

    <!--
    Most controllers will use the ControllerClassNameHandlerMapping above, but
    for the index controller we are using ParameterizableViewController, so we must
    define an explicit mapping for it.
    -->
    <bean id="urlMapping" class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping">
        <property name="mappings">
            <props>
                <prop key="index.htm">indexController</prop>
            </props>
        </property>
    </bean>

    <bean id="viewResolver"
          class="org.springframework.web.servlet.view.InternalResourceViewResolver"
          p:prefix="/WEB-INF/jsp/"
          p:suffix=".jsp" />

    <!--
    The index controller.
    -->
    <bean name="indexController"
          class="org.springframework.web.servlet.mvc.ParameterizableViewController"
          p:viewName="index" />

</beans>

But where do I need to insert some entries to let my RegisterController do work? 但是我需要在哪里插入一些条目来让RegisterController正常工作?

Since you gave *.htm in url pattern, the dispatcher-servlet will only recognize *.htm requests. 由于您以网址格式提供了* .htm,因此分派器servlet将仅识别* .htm请求。 Change your web.xml 更改您的web.xml

<servlet-mapping>
        <servlet-name>dispatcher</servlet-name>
        <url-pattern>/*</url-pattern>
</servlet-mapping> 

And above your controller, there's no need to give RequestMapping . 在您的控制器上方,无需提供RequestMapping Your methods will do the work for you 您的方法将为您效劳

@Controller
public class RegisterController {

And above your method, you should give value so that your method can find it 在您的方法之上,您应该给予价值,以便您的方法可以找到它

@RequestMapping(value="/register.htm" method=RequestMethod.GET)
public String viewRegistration(Model model)

According to Dispatcher Servlet mapping, your RequestMapping will go to the controller with HttpRequest with .htm extension.. In your case, you have mentioned *.htm 根据Dispatcher Servlet映射,您的RequestMapping将以扩展名为.htm的HttpRequest进入控制器。在您的情况下,您提到的* .htm

<servlet-mapping>
        <servlet-name>dispatcher</servlet-name>
        <url-pattern>*.htm</url-pattern>
</servlet-mapping>

So in the controller, for the appropriate request, add like this.. 因此,在控制器中,对于适当的请求,请像这样添加。

@RequestMapping(value="/register.htm" method=RequestMethod.GET)
    public String viewRegistration(Model model){

and In the top of the controller, add like this, 然后在控制器顶部添加这样的内容,

@Controller
@RequestMapping("/")
public class RegisterController {

add this in spring.xml, 在spring.xml中添加它,

<context:component-scan base-package="RegisterController" />

including package name of Controller should be there in component-scan base-package... 包括Controller的软件包名称应在component-scan基本软件包中存在...

Edit servlet mapping in you web.xml as: web.xml servlet映射编辑为:

 <servlet-mapping>
        <servlet-name>dispatcher</servlet-name>
        <url-pattern>/</url-pattern>
 </servlet-mapping>

And also add below piece of code in your spring configuration file: 并且在您的spring配置文件中添加以下代码:

<mvc:annotation-driven></mvc:annotation-driven>
<context:component-scan base-package="your.packagename.RegisterController"></context:component-scan>

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