[英]Segmentation fault in 2D array unsigned char using calloc in C
I've trying to allocate an unsigned char**
using calloc : 我试图使用calloc分配一个unsigned char**
:
newmatriz = (unsigned char**) calloc(width, sizeof(unsigned char));
for (j=0 ; j < width; j++)
{
if (newmatriz[j]=(unsigned char*)calloc(witdh, sizeof(unsigned char)) == NULL){
printf("Memory allocation error. Exit program\n");
exit(1);
}
}
for (i=0;i<width;i++)
{
for(j=0;j<width;j++)
{
newmatriz[i][j] = 0;
}
}
But I get segmentation fault when I'm trying to acces the pos [i][j] 但是当我试图访问pos [i] [j]时,我得到了分段错误
Is problem be related to the use int as iterator? 问题与使用int作为迭代器有关吗?
There is a typo in this statement. 这句话中有一个拼写错误。 Instead of sizeof( unsigned char )
you have to use sizeof( unsigned char * )
而不是sizeof( unsigned char )
你必须使用sizeof( unsigned char * )
newmatriz = (unsigned char**) calloc(width, sizeof(unsigned char *));
^^^^^^
Also this if statement is incorrect 此if语句也是错误的
if ( newmatriz[j] = calloc(witdh, sizeof(unsigned char) ) == NULL){
In this statement newmatriz[j]
is set either to 1 or 0 depending on whether the memory allocation was successfull or not. 在此语句中, newmatriz[j]
被设置为1或0,具体取决于内存分配是否成功。
I think you mean 我想你的意思是
if ( ( newmatriz[j] = calloc(witdh, sizeof(unsigned char) ) ) == NULL){
And these loops 而这些循环
for (i=0;i<width;i++)
{
for(j=0;j<width;j++)
{
newmatriz[i][j] = 0;
}
}
do not make sense because calloc
already initialized the allocated memory by zeroes. 没有意义,因为calloc
已经用零初始化了分配的内存。
The answer is simple newmatriz is an array (aka pointer) to unsigned char* you are allocation unsigned char simply change the top line to allocate the correctly sized array, in this case you want an array of byte size width*sizeof(unsigned char*)
not width*sizeof(unsigned char)
as you currently have it. 答案是简单的newmatriz是一个数组(也就是指针)到unsigned char *你是分配unsigned char只需改变顶行来分配正确大小的数组,在这种情况下你需要一个字节大小width*sizeof(unsigned char*)
的数组width*sizeof(unsigned char*)
不是你现在拥有的width*sizeof(unsigned char)
。
newmatriz = (unsigned char**) calloc(width, sizeof(unsigned char*));
for (j=0 ; j < width; j++){
if (newmatriz[j]=(unsigned char*)calloc(witdh, sizeof(unsigned char)) == NULL){
printf("Memory allocation error. Exit program\n");
exit(1);
}
}
In the second calloc()
there are some brackets missing: 在第二个calloc()
有一些括号丢失:
if (newmatriz[j] = calloc(witdh, sizeof(unsigned char)) == NULL){
should be 应该
if ((newmatriz[j] = calloc(witdh, sizeof(unsigned char))) == NULL){
Without that, calloc()
s result is compared with NULL and the result of the comparison instead of the pointer is stored in newmatriz[j]
没有它, calloc()
的结果与NULL进行比较,而比较的结果而不是指针存储在newmatriz[j]
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