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使用XSLT根据几个子元素对XML进行排序

[英]Sorting XML based on several sub-elements using XSLT

I'm trying to sort some XML (using XSLT) based on a few child elements and return the result as XML. 我正在尝试根据一些子元素对一些XML进行排序(使用XSLT),并将结果作为XML返回。 I know it's probably not that difficult but this is my first experience using XSLT and it's giving me some troubles. 我知道这可能并不困难,但这是我第一次使用XSLT,这给我带来了一些麻烦。 Here's the XML: 这是XML:

<root>
  <subject>
    <courseSubjectHeader>
        <subjectCode>B</subjectCode>
        <subjectName>text</subjectName>
        <unit>text</unit>
        <faculty>text</faculty>
    </courseSubjectHeader>
    <course>
      <crsLevel>text</crsLevel>
      <subjectAndNumber>B 200</subjectAndNumber>
      <units>3.0</units>
      <hours>3-0</hours>
    </course>
    <course>
      <crsLevel>text</crsLevel>
      <subjectAndNumber>B 100</subjectAndNumber>
      <units>3.0</units>
      <hours>3-0</hours>
    </course>
  </subject>
  <subject>
    <courseSubjectHeader>
        <subjectCode>C</subjectCode>
        <subjectName>text</subjectName>
        <unit>text</unit>
        <faculty>text</faculty>
    </courseSubjectHeader>
    <course>
      <crsLevel>text</crsLevel>
      <subjectAndNumber>C 300</subjectAndNumber>
      <units>3.0</units>
      <hours>3-0</hours>
    </course>
    <course>
      <crsLevel>text</crsLevel>
      <subjectAndNumber>C 100</subjectAndNumber>
      <units>3.0</units>
      <hours>3-0</hours>
    </course>
  </subject>
  <subject>
    <courseSubjectHeader>
        <subjectCode>A</subjectCode>
        <subjectName>text</subjectName>
        <unit>text</unit>
        <faculty>text</faculty>
    </courseSubjectHeader>
    <course>
      <crsLevel>text</crsLevel>
      <subjectAndNumber>A 300</subjectAndNumber>
      <units>3.0</units>
      <hours>3-0</hours>
    </course>
    <course>
      <crsLevel>text</crsLevel>
      <subjectAndNumber>A 200</subjectAndNumber>
      <units>3.0</units>
      <hours>3-0</hours>
    </course>
  </subject>
</root>

I'd like to sort the 'subjects' by their 'subjectCode' child element, and all the courses within each subject by their 'subjectAndNumber' child element. 我想按“ subjectCode”子元素对“ subject”进行排序,并按“ subjectAndNumber”子元素对每个主题中的所有课程进行排序。 So the resulting XML would be... 因此,生成的XML将是...

<root>
  <subject>
    <courseSubjectHeader>
        <subjectCode>A</subjectCode>
        <subjectName>text</subjectName>
        <unit>text</unit>
        <faculty>text</faculty>
    </courseSubjectHeader>
    <course>
      <crsLevel>text</crsLevel>
      <subjectAndNumber>A 200</subjectAndNumber>
      <units>3.0</units>
      <hours>3-0</hours>
    </course>
    <course>
      <crsLevel>text</crsLevel>
      <subjectAndNumber>A 300</subjectAndNumber>
      <units>3.0</units>
      <hours>3-0</hours>
    </course>
  </subject>
  <subject>
    <courseSubjectHeader>
        <subjectCode>B</subjectCode>
        <subjectName>text</subjectName>
        <unit>text</unit>
        <faculty>text</faculty>
    </courseSubjectHeader>
    <course>
      <crsLevel>text</crsLevel>
      <subjectAndNumber>B 100</subjectAndNumber>
      <units>3.0</units>
      <hours>3-0</hours>
    </course>
    <course>
      <crsLevel>text</crsLevel>
      <subjectAndNumber>B 200</subjectAndNumber>
      <units>3.0</units>
      <hours>3-0</hours>
    </course>
  </subject>
  <subject>
    <courseSubjectHeader>
        <subjectCode>C</subjectCode>
        <subjectName>text</subjectName>
        <unit>text</unit>
        <faculty>text</faculty>
    </courseSubjectHeader>
    <course>
      <crsLevel>text</crsLevel>
      <subjectAndNumber>C 100</subjectAndNumber>
      <units>3.0</units>
      <hours>3-0</hours>
    </course>
    <course>
      <crsLevel>text</crsLevel>
      <subjectAndNumber>C 300</subjectAndNumber>
      <units>3.0</units>
      <hours>3-0</hours>
    </course>
  </subject>
</root>

And finally, here's my (pretty awful) attempt at the XSLT: 最后,这是我对XSLT的尝试(非常糟糕):

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
     xmlns:xsl="http://www.w3.org/1999/ /Transform">

    <xsl:output method="xml" indent="yes"/>
    <xsl:strip-space elements="*"/>

    <xsl:template match="@*|node()">
        <xsl:copy>
            <xsl:apply-templates select="@*|node()"/>
        </xsl:copy>
    </xsl:template>

    <xsl:template match="/">
        <xsl:copy>
            <xsl:apply-templates select="subject">
                <xsl:sort select="subjectCode"/>
            </xsl:apply-templates>
        </xsl:copy>
    </xsl:template>

    <xsl:template match="subject">
        <xsl:copy>
            <xsl:apply-templates select="course">
                <xsl:sort select="subjectAndNumber"/>
            </xsl:apply-templates>
        </xsl:copy>
    </xsl:template>

</xsl:stylesheet>

Any help would be much appreciated, thanks! 任何帮助将不胜感激,谢谢!

You only have a few minor mistakes - compare: 您只有几个小错误-比较:

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:strip-space elements="*"/>

<xsl:template match="@*|node()">
    <xsl:copy>
        <xsl:apply-templates select="@*|node()"/>
    </xsl:copy>
</xsl:template>

<xsl:template match="/*">
    <xsl:copy>
        <xsl:apply-templates select="subject">
            <xsl:sort select="courseSubjectHeader/subjectCode"/>
        </xsl:apply-templates>
    </xsl:copy>
</xsl:template>

<xsl:template match="subject">
    <xsl:copy>
        <xsl:copy-of select="courseSubjectHeader"/>
        <xsl:apply-templates select="course">
            <xsl:sort select="subjectAndNumber"/>
        </xsl:apply-templates>
    </xsl:copy>
</xsl:template>

</xsl:stylesheet>

Note : your most serious mistake is this: xmlns:xsl="http://www.w3.org/1999/ /Transform" . 注意 :您最严重的错误是: xmlns:xsl="http://www.w3.org/1999/ /Transform" If you don't declare the XSLT namespace properly, then your document is not a stylesheet at all. 如果您没有正确声明XSLT命名空间,则您的文档根本不是样式表。

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