[英]Sum of all sub-elements XML/XSLT
How would I add all the numerical elements of all the sub elements for each parent?我如何为每个父元素添加所有子元素的所有数字元素?
Example:例子:
<root>
<parent id="1">
<values>
<valuea>1</valuea>
<valueb>2</valueb>
<valuec>3</valuec>
</vlaues>
</parent>
<parent id="2">
<values>
<valuea>1</valuea>
<valuec>3</valuec>
</vlaues>
</parent>
</root>
I need the XSLT when going through each parent to produce the sum of all the values.在通过每个父级生成所有值的总和时,我需要 XSLT。 Parent 1 should return a sum of 6, Parent 2 a sum of 4. As you can see, each parent will have a different amount of values.父项 1 应返回总和 6,父项 2 应返回总和 4。如您所见,每个父项将具有不同数量的值。 How can I write to simply sum every value under values, regardless of their names?我如何写来简单地总结值下的每个值,而不管它们的名字?
Simply use the sum() function like this:只需像这样使用sum()函数:
<xsl:template match="values">
<sum><xsl:copy-of select="sum(*)" /></sum>
</xsl:template>
It creates a <sum>
element with the desired value.它创建一个具有所需值的<sum>
元素。
In a whole stylesheet this could look like the following:在整个样式表中,这可能如下所示:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output indent="yes"/>
<!-- Identity template -->
<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="values">
<sum><xsl:copy-of select="sum(*)" /></sum>
</xsl:template>
</xsl:stylesheet>
Its output is它的输出是
<root>
<parent id="1">
<sum>6</sum>
</parent>
<parent id="2">
<sum>4</sum>
</parent>
</root>
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