如何在C ++中将字符串时间转换为unsigned int

Question

I need to convert string time to unsigned int i test my program with atoi/strtoul/atol and string stream but they don't work correctly what am i missing???

 string CurrentTime(){
        time_t rawtime;
        struct tm * timeinfo;
        char bffr [80];

        time (&rawtime);
        timeinfo = localtime (&rawtime);

        strftime (bffr,80,"%T",timeinfo);
        // puts (bffr);

        return bffr;
    }

    int main(){
    string new_time;
    new_time = CurrentTime();
    stringstream strValue;
        strValue << new_time;
    unsigned int stime;
        strValue >> stime;
    cout<<stime<<endl;
    cout<<new_time<<endl;
    }

and

 int main(){
        string new_time;
        new_time = CurrentTime();
unsigned int stime =atoi(new_time.c_str());
cout<<stime<<endl;
cout<<new_time<<endl;

but both of them print stime :just only hour for example 10

and print new_time : for example 10:20:15

Answer 1

Your string stream is not working because of a delimiter ":". you need to get around it. Try the following code:

string new_time;
new_time = CurrentTime();
std::string finalstring;
std::string delim = ":";
size_t pos = 0;
while ((pos = new_time.find(delim)) != std::string::npos)
{
    finalstring += new_time.substr(0, pos);
    new_time.erase(0, pos + delim.length());
}

stringstream strValue;
strValue << finalstring;
strValue << new_time;
unsigned int stime;
strValue >> stime;
cout << stime << endl;

Answer 2

It seems that %T doesn't work well with strftime function call.

But there is a workaround for this. %T is actually %H:%M:%S

Thus,

strftime (bffr, 80, "%H:%M:%S", timeinfo);

should work fine for your code.