[英]Python: return statement still returns none from function
I've looked at all of the other "Returns none" questions on here and none of them seem to solve my problem. 我在这里查看了所有其他“不归还”问题,但这些问题似乎都无法解决我的问题。
rates = []
for date in unformatted_returns: # Please ignore undefined variables, it is redundant in this context
if date[0] >= cutoff_date:
date_i = unformatted_returns.index(date)
r = date_initialize(date[0], date_i)
print "r is returned as:", r
rates.append(r)
print date[0]
else:
continue
def date_initialize(date, date_i):
print " initializing date configuration"
# Does a bunch of junk
rate_of_return_calc(date_new_i, date_i)
def rate_of_return_calc(date_new_i, date_i):
r_new = unformatted_returns[int(date_i)] # Reverse naming, I know
r_old = unformatted_returns[int(date_new_i)] # Reverse naming, I know
if not r_new or not r_old:
raise ValueError('r_new or r_old are not defined!!')
# This should never be true and I don't want anything returned from here anyhow
else:
ror = (float(r_new[1])-float(r_old[1]))/float(r_old[1])
print "ror is calculated as", ror
return ror
The functions them selves work fine, the output is like so: 他们自己选择的功能运行良好,输出如下:
initializing date configuration
('2014-2-28', u'93.52')
ror is calculated as -0.142643284859
r is returned as: None
2015-2-2
>>>
ror
is the correct value, but why does it not get returned when I have it written right there return ror
?? ror
是正确的值,但是当我在正确的位置写return ror
时为什么不返回它? Doesn't make any sense to me 对我没有任何意义
You need to return it here too 您也需要在这里退货
def date_initialize(date, date_i):
print " initializing date configuration"
# Does a bunch of junk
return rate_of_return_calc(date_new_i, date_i)
In date_initialize
, you need to return the function that is returning the value that you want. 在
date_initialize
,您需要返回正在返回所需值的函数。 Explicitly, change your call from 明确地,从
rate_of_return_calc(date_new_i, date_i)
to 至
return rate_of_return_calc(date_new_i, date_i)
Your first call, to date_initialize
, does not return anything. 您第一次调用
date_initialize
不会返回任何内容。 Therefore, when you call rate_of_return_calc
, you receive the value and then throw it away. 因此,当您调用
rate_of_return_calc
,您会收到该值,然后将其丢弃。 You need to return it to pass the value along to your main function. 您需要返回它,以将值传递给您的主函数。
You need to return the value in date_initialize too: 您还需要在date_initialize中返回值:
def date_initialize(date, date_i):
print " initializing date configuration"
# Does a bunch of junk
return rate_of_return_calc(date_new_i, date_i)
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