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python - 返回返回无

[英]python - return returns None

I wrote a function which gets two numbers and an operation (string) and returns the result of the two numbers with the given operation.我编写了一个函数,它获取两个数字和一个操作(字符串),并使用给定的操作返回两个数字的结果。 For example calculate_matehamatical_expression(5,6,'+') should return 11. I divide the the assignment to little functions, but when I call these little function it always returns None.例如,calculate_matehamatical_expression(5,6,'+') 应该返回 11。我将分配分配给小函数,但是当我调用这些小函数时,它总是返回 None。 Can someone explain to me why that happens?有人可以向我解释为什么会这样吗? This is the Code I wrote:这是我写的代码:

def mathematical_sum(num1,num2):
    return num1 + num2

def mathematical_difference(num1,num2):
    return num1 - num2

def mathematical_product(num1,num2):
    return num1 * num2

def mathematical_division(num1,num2):
    if num2 != 0:
        return num1 / num2
    else:
        return None

def operation_error(operation):
    if operation != "+" or operation != "-" or operation != "*" or operation != "/":
        return None




def calculate_mathematical_expression(num1,num2,operation):
    if operation == "+":
        mathematical_sum(num1,num2)
    elif operation == "-":
        mathematical_difference(num1,num2)
    elif operation == "*":
        mathematical_product(num1,num2)
    elif operation == "/":
        mathematical_division(num1,num2)
    else:
        operation_error(operation)

You need to return again inside calculate_mathematical_expression , eg:您需要在calculate_mathematical_expression再次返回,例如:

def calculate_mathematical_expression(num1,num2,operation):
    if operation == "+":
        return mathematical_sum(num1,num2)

The return in mathematical_sum doesn't affect the function it's being called from.在返回mathematical_sum并不影响它被从调用的函数。

You need to return你需要return

When you return from a function, it only returns to the function that called it.当您return从功能,它只返回到调用它的功能。 So when you return in mathematical_sum() , the value is returned to calculate_mathematical_expression() & you need to return again from this function, like this:因此,当您在mathematical_sum() return时,该值将返回到calculate_mathematical_expression()您需要从该函数中再次返回,如下所示:

if operation == "+":
    return mathematical_sum(num1,num2)
elif operation == "-":
    return mathematical_difference(num1,num2)
elif operation == "*":
    return mathematical_product(num1,num2)
elif operation == "/":
    return mathematical_division(num1,num2)
else:
    return operation_error(operation)

...otherwise calculate_mathematical_expression() returns None . ...否则calculate_mathematical_expression()返回None


operation_error() does not work operation_error()不起作用

  • Use and instead of or .使用and代替or Otherwise your condition will always be True否则您的条件将始终为True
  • Return a boolean, not None .返回一个布尔值,而不是None Here, your function always return None在这里,你的函数总是返回None

Example:例子:

def operation_error(operation):
    return operation != "+" and operation != "-" and operation != "*" and operation != "/"

You don't need operation_error()你不需要operation_error()

Since you have a condition for each operator, you don't need the operation_error() function, you can directly do this:由于您对每个运算符都有一个条件,因此您不需要operation_error()函数,您可以直接执行此操作:

else:
    return None

...or even remove the else statement and let calculate_mathematical_expression() automatically return None when reaching its end. ...或者甚至删除else语句并让calculate_mathematical_expression()在到达结束时自动返回None

Your calculate_mathematical_expression function is not returning anything.您的 calculate_mathematical_expression 函数没有返回任何内容。 Try following code:尝试以下代码:

def calculate_mathematical_expression(num1,num2,operation):
    if operation == "+":
        return mathematical_sum(num1,num2)
    elif operation == "-":
        return mathematical_difference(num1,num2)
    elif operation == "*":
        return mathematical_product(num1,num2)
    elif operation == "/":
        return mathematical_division(num1,num2)
    else:
        return operation_error(operation)

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