在Java中的单个字符串数组中对逗号分隔的数字进行排序

Question

I have one String array:

String[] digits = {"2,5,1,6"};

I want to sort this string array, without using a temp variable in Java.

Like this 1,2,5,6

Answer 1

Since Java 8 you can write something like

String[] digits = { "2,11,5,1,6" };
digits[0] = Stream.of(digits[0].split(","))
        .mapToInt(Integer::parseInt)//convert value to int
        .sorted()//sort integer values
        .mapToObj(String::valueOf)//convert values back to String
        .collect(Collectors.joining(","));//join values using "," delimiter

System.out.println(digits[0]);

Output: 1,2,5,6,11

Answer 2

String [] digits = string.split(",");
Arrays.sort( digits );
System.out.println(Arrays.toString(digits));

Answer 3

You can use it like this:

List<String> list = new ArrayList<String>(Arrays.asList(string.split(",")));
Collections.sort(list);

Answer 4

first you need to convert the items inside the digits array into integers

int [] forSorting = new int [digits.lenght];

for(int x = 0; x < digits.length; x++){

 forSorting [x] = Integer.parseInt(digits [x]);

}

//sort forSorting here