在Java中将泛型范围实现为函数参数的最佳方法是什么？

Question

I have a function that needs a range as an argument. The domain is [0-100] and it includes 0 and 100. The range argument could for example be:

[1-8, 18, 20-88, 90-92]

or

[1, 10-30]

Ranges do not overlap. I am interested in the mechanism - how best to pass a range argument? Array? or use variable argument?

Answer 1

Use a list of Range objects:

class Range
{
    int low;
    int high;

    Range(int low, int high)
    {
        this.low = low;
        this.high = high;
    }
}

List<Range> rangeArray = new ArrayList<Range>();

then assign ranges like this:

rangeArray.add(new Range(1,8));
rangeArray.add(new Range(18,18));
rangeArray.add(new Range(20,88));
rangeArray.add(new Range(90,92));

Answer 2

Have a static method r() that creates a range in some representation

func( r(1,8), r(18), r(20,88), r(90,92) )

Or use method chaining to create a list of ranges

func( Range.r(1,8).r(18).r(20,88).r(90,92) )

Or, as my joke comment

func(1,-8, 18, 20,-88, 90,-92)

Or, use 100*x+y to represent (x,y)

func( 1_08, 18, 20_88, 90_92 );