Python socket.connect（）错误出

Question

Python version 2.7.3

Python code, interactive mode

import socket
socket.setdefaulttimeout(2)
s = socket.socket()
s.connect(("192.168.95.148",21))

Errors out

>>> s.connect(("192.168.95.148",21))
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/lib/python2.7/socket.py", line 224, in meth
    return getattr(self._sock,name)(*args)
socket.timeout: timed out

Syntax looks correct. I even tried with another IP address that is pingable and same error.

Thanks!

Answer 1

I am looking at the port you are using (21) and it's the FTP port.

https://en.wikipedia.org/wiki/List_of_TCP_and_UDP_port_numbers

I don't see any errors in your code per se, but here some things I am worried about:

a) A lot of places lock down and turn off FTP , telnet , etc. ports that are historically used, but in today's security consious world, we use scp and ssh (instead of ftp and ssh ). You might talk to your system administrators and see if that service is even turned on, or let alone your filewall even allows that port to go through.

b) I am not used to seeing the default parameters, but I assume you want

socket(socket.AF_INET, socket.SOCK_STREAM)

I have Python 2.6, and that is the defaults for that (which I assume is the same for 2.7).

c) I would try this on different ports to see if it is a port problem. Of course, the early numbered ports are special "well-known ports" that normal users can't use. I usually use port 9711 or 8888.

d) I would also try it without the timeout and see if that works.

I hope this helps!

Answer 2

这不是您问题的直接答案，但是如果您要进行FTP传输，我可以建议使用标准ftplib模块吗？