在最后一个匹配元素之后选择XML元素

Question

I have XML file that looks like:

<Meal>
    <MealName>Lunch</MealName>
    <MealData>blahblahblah</MealData>
    <MealTime>2015-03-12</MealTime>
</Meal>
<Meal>
    <MealName>Dinner</MealName>
    <MealData>lolololol</MealData>
    <MealTime>2015-04-27</MealTime>
</Meal>

I'd like to select MealName and MealData of the last Meal instance.

I can do everything else I need with simple LINQ queries just fine. For example, to get data from last week's meals, I do:

XElement noIdea = XElement.Load(".../.../meal.xml");
DateTime d = DateTime.Today.AddDays(-7);
int offset = d.DayOfWeek - DayOfWeek.Monday;
        DateTime lastMonday = d.AddDays(-offset);
        DateTime lastSunday = lastMonday.AddDays(6);
        IEnumerable<XElement> idkMealTime =
                    from el in noIdea.Elements("Meal")
                    where DateTime.Compare(Convert.ToDateTime(el.Element("MealTime").Value), lastMonday) > 0 &&
                    DateTime.Compare(Convert.ToDateTime(el.Element("MealTime").Value), lastSunday) < 0
                    select el;
        WhatHaveYouEaten(idkMealTime);

But this one is different and I can't figure it out.

Help is appreciated.

Answer 1

Simply select the last meal element:

var lastMeal = noIdea.Elements("Meal").Last();

As an aside, you can simply cast an element to DateTime rather than converting the string value - eg (DateTime)el.Element("MealTime") . This uses DateTime.Parse internally with the correct styles as allowed in the XML specification.