[英]Is it possible to dump the core but not exit the process?
I want to be able to generate a core dump but not exit the process afterwards. 我希望能够生成核心转储,但之后不会退出该进程。 I don't need it to continue execution, just not die.
我不需要它继续执行,只是不死。 This is a C++ Ubuntu process.
这是一个C ++ Ubuntu进程。
I believe I'm dumping the core in a pretty standard way: I catch the offending signal via setting the signal handler with signal(), I set the core size limit via setrlimit() and then I prompt the core dump with signal() and raise(): 我相信我正在以一种非常标准的方式倾倒核心:我通过使用signal()设置信号处理程序来捕获有问题的信号,我通过setrlimit()设置核心大小限制然后我用signal()提示核心转储和raise():
signal(SIGSEGV, OnPosixSignal);
...
void OnPosixSignal(int iSignal)
{
struct rlimit CoreLimit;
CoreLimit.rlim_cur = RLIM_INFINITY;
CoreLimit.rlim_max = RLIM_INFINITY;
setrlimit(RLIMIT_CORE, &CoreLimit);
signal(iSignal, SIG_DFL);
raise(iSignal);
}
Is there something I can do to not have the process exit after dumping the core? 在卸载核心后,我有什么办法可以让流程退出吗?
Thanks a bunch in advance! 提前谢谢!
You can also do that using gcore
: 你也可以使用
gcore
做到这gcore
:
Generate a core dump of a running program with process ID pid.
使用进程ID pid生成正在运行的程序的核心转储。 Produced file is equivalent to a kernel produced core file as if the process crashed (and if "ulimit -c" were used to set up an appropriate core dump limit).
生成的文件相当于内核生成的核心文件,就像进程崩溃一样(如果“ulimit -c”用于设置适当的核心转储限制)。 Unlike after a crash, after gcore the program remains running without any change.
与崩溃后不同,在gcore之后程序仍在运行而没有任何变化。
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