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从矩阵中获得与R中其他列具有相同值的值

[英]get value from matrix that have same value in other column in R

I have matrix that contains 2 columns. 我有包含2列的矩阵。 First column name is fuzzified and the second is relasifuzzi. 第一列名称被模糊化,第二列是relasifuzzi。

fuzzified  relasifuzzi
        1            2
        2            3
        3            5
        5            9
        9            8
        9           10
        9            7 

I want to make a group like this: 我想组成一个这样的小组:

fuzzified  relasifuzzi
        1            2
        2            3
        3            5
        5            9
        9            8, 10, 7

How can I get like this in R? 如何在R中得到这样的结果?

    library(data.table)
    setDT(k1)[,.(relasifuzzi=paste(relasifuzzi,collapse=",")),by=fuzzified]
   fuzzified relasifuzzi
1:         1           2
2:         2           3
3:         3           5
4:         5           9
5:         9      8,10,7

data 数据

k1<-structure(list(fuzzified = c(1L, 2L, 3L, 5L, 9L, 9L, 9L), relasifuzzi = c(2L, 
3L, 5L, 9L, 8L, 10L, 7L)), .Names = c("fuzzified", "relasifuzzi"
), class = "data.frame", row.names = c(NA, -7L))

Assuming your data is in a data.frame called "df", try: 假设您的数据位于名为“ df”的data.frame ,请尝试:

library("dplyr")

df %>% group_by(fuzzified) %>% 
   summarize(relasifuzzi = paste(relasifuzzi, collapse = ", "))

or: 要么:

library("plyr")

ddply(df, .(fuzzified), summarize, relasifuzzi = paste(relasifuzzi, collapse = ", "))

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