Python正则表达式替换字符串

Question

I have the following code: 我有以下代码：

 a="32<2>fdssa</2>ffdsa32"
 re.sub(r'<(\d+)>|</(\d+)>',"item",a)

The result I get: 我得到的结果是：

32itemfdssaitemffdsa32

I want the result: 我想要结果：

32<item>fdssa</item>ffdsa32

Answer 1

You need to capture </ part. 您需要捕获</ part。

re.sub(r'(</?)\d+>',r"\1item>",a)

Since I made / as optional, (</?) will capture < or </ 由于我将/设为可选，所以(</?)将捕获<或</

Example: 例：

>>> a="32<2>fdssa</2>ffdsa32"
>>> re.sub(r'(</?)\d+>',r"\1item>",a)
'32<item>fdssa</item>ffdsa32'

Answer 2

>>> re.sub(r'(</?)\d+(?=>)', r'\1item', a)
'32<item>fdssa</item>ffdsa32'

(</?) matches < or </ captures to \\1 (</?)匹配<或</捕获到\\1
\\d+ matches one or more digits. \\d+匹配一个或多个数字。
(?=>) positive look ahead, checks if the digits is followed by > , but doesn't consume them (?=>)积极向前看，检查数字后面是否有> ，但不消耗它们