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用正则表达式用 python 中的字符串列表替换字符串

[英]Replace with regular expression a string with a list of strings in python

I want to replace part of a string with a list of strings我想用字符串列表替换字符串的一部分

Eg.例如。 with an input string of '{"abc": "##value##", "Xyz": 2}' , I want to replace "##value##" with some list like ["v1", "v2"]输入字符串为'{"abc": "##value##", "Xyz": 2}' ,我想用["v1", "v2"]类的列表替换"##value##" " ["v1", "v2"]

So, the output would look like '{"abc": ["v1", "v2"], "Xyz": 2}'因此,output 看起来像'{"abc": ["v1", "v2"], "Xyz": 2}'

If the replacement were not a list I would have just used如果替换不是我刚刚使用的列表

re.sub('##value##', replacement_value, input_data) , however doing so gives an error of unhashable type: 'list' re.sub('##value##', replacement_value, input_data) ,但是这样做会产生不可unhashable type: 'list'

Is there another way to achieve this?还有另一种方法可以实现这一目标吗?

Simply change简单地改变

re.sub('##value##', replacement_value, input_data)

to

re.sub("'##value##'", str(replacement_value), input_data)

re.sub() only takes in strings as the substitutes, so it's the equivalent of re.sub()只接受字符串作为替代,所以它相当于

import re
s = '{"abc": "##value##", "Xyz": 2}'
print(re.sub('"##value##"',  '["v1", "v2"]', s))

Output: Output:

{"abc": ["v1", "v2"], "Xyz": 2}

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