如何用字典作为值反转列表中的键值对？

Question

I have a key value pair as below:

((1,{'foo':1,'abc':2,'xyz':3,'def':2}),(2,{'ghu':3,'kie':2}))

I was able to reverse the key value pair to below form:

((({'foo':1,'abc':2,'xyz':3,'def':2}),1),(({'ghu':3,'kie':2})),2)

But I need the in them in the following format.Tried with various options but was not successful

(({'foo':1}),1)
(({'abc':2}),1)
(({'xyz':3}),1)
(({'def':2}),1)
(({'ghu':3}),2)
(({'kie':2}}),2)

Could any one help me with this?

Answer 1

This list comprehension will produce your desired format:

l = ((1,{'foo':1,'abc':2,'xyz':3,'def':2}),(2,{'ghu':3,'kie':2}))
tuple((({k:v}),i) for i,j in l for k,v in j.items())

Answer 2

If tuple is what you want, then you can use a simple generator expression like the following and then pass it to tuple() function to get the required tuple.

Example -

>>> t = ((1,{'foo':1,'abc':2,'xyz':3,'def':2}),(2,{'ghu':3,'kie':2}))
>>>
>>> nt = tuple((({k:d[k]}),i) for i, d in t for k in d.keys())
>>> nt
(({'def': 2}, 1), ({'xyz': 3}, 1), ({'abc': 2}, 1), ({'foo': 1}, 1), ({'kie': 2}, 2), ({'ghu': 3}, 2))

Answer 3

1. Iterate on every item from the given tuple.
2. Iterate second element for the item ie dictionary part.
3. create new item ie (({key:value},), item[0])
4. Append result into output variable.

Code:

input_val = ((1,{'foo':1,'abc':2,'xyz':3,'def':2}),(2,{'ghu':3,'kie':2}))

output_val = []
for i in input_val:
    for key, value in i[1].items():
        output_val.append( (({key:value},), i[0]))

import pprint
pprint.pprint(output_val)

Output:

[(({'xyz': 3},), 1),
 (({'foo': 1},), 1),
 (({'abc': 2},), 1),
 (({'def': 2},), 1),
 (({'ghu': 3},), 2),
 (({'kie': 2},), 2)]