带两个正则表达式参数的fnmatch函数

Question

Can we use fnmatch with two regular expressions?

For example, if I use fnmatch("file*", "*", 0) , will it match in this case?

Answer 1

否。fnmatch的模式不是正则表达式-根据python标准lib文档，它们是“ Unix shell样式通配符”

Answer 2

For example, if I use fnmatch("file*", "*", 0) , will it match in this case?

Yes, of course it will, once you remove the redundant third parameter:

>>> from fnmatch import fnmatch
>>> fnmatch("file*", "*")
True

However, it is not matching because it's interpreting both arguments as regular expressions; it matches because the pattern "*" will match any input for filename , including "file*" . You can see this in the source code :

return re_pat.match(name) is not None

name (which is filename , the first argument to fnmatch ) isn't being used as a regex, it's just the string that gets passed to re.match .

You can also see from the code that the second argument, the pattern , is translated rather than being used directly as a regular expression, as the "Unix shell-style wildcards" syntax is not regex. I suggest you read the documentation .

Can we use fnmatch with two regular expressions?

No, we can't.

Answer 3

fnmatch is for matching filenames to "shell-style" expression (not regex to be clear). I have no idea what you're trying to accomplish, but in short, no. You need to give it a specific filename and then a pattern to match it to, it doesn't try to see if two patterns are consistent.

Answer 4

No, you can't use fnmatch like that. They are not regex in the way you are using it. You need to give it a specific filename and then a pattern to match it to, it doesn't try to see if two patterns are consistent.