[英]Difference between the two method references to instance methods
import java.util.List;
import java.util.function.*;
interface SomeTest <T>
{
boolean test(T n, T m);
}
class MyClass <T>
{
boolean myGenMeth(T x, T y)
{
boolean result = false;
// ...
return result;
}
}
class Timepass
{
public static void main(String args[])
{
SomeTest <Integer> mRef = MyClass <Integer> :: myGenMeth; //Statement 1
Predicate <List<String>> p = List<String> :: isEmpty; //Statement 2
}
}
In the above code, Statement 1
produces two compile time errors 在上面的代码中, Statement 1
产生两个编译时错误
1- Can not find method
myGenMeth(Integer, Integer)
1-找不到方法myGenMeth(Integer, Integer)
2- Non static method
myGenMeth(T, T)
can not be referenced from static context 2-无法从静态上下文引用非静态方法myGenMeth(T, T)
Where as, Statement 2
shows no error. 其中, Statement 2
没有显示错误。
1- What is the difference between Statement 1
and Statement 2
?? 1- Statement 1
和Statement 2
什么区别?
Statement 2
is working fine. 2- Statement 2
的运作情况良好。 Statement 1
is producing error). (我不是问Statement 1
为何产生错误)。 Because you have method references to instance methods, but don't specify any specific instance, the instance needs to be passed as a parameter to the interface method. 因为您具有对实例方法的方法引用,但未指定任何特定实例,所以需要将实例作为参数传递给接口方法。
For statement 2, you can pass this instance to the test
method of Predicate
: 对于语句2,您可以将此实例传递给Predicate
的test
方法:
p.test(new ArrayList<>());
But for statement 1, test
doesn't take an instance as a parameter: 但是对于语句1, test
不将实例作为参数:
mRef.test(new MyClass<>(), 1, 2);
To make this compile, SomeTest
needs to be changed to: 为了进行此编译,需要将SomeTest
更改为:
interface SomeTest<T> {
boolean test(MyClass<T> instance, T n, T m);
}
Alternatively, you can make the method references refer to specific instances, then the interface method doesn't need to contain that parameter: 另外,您可以使方法引用引用特定的实例,然后接口方法不需要包含该参数:
SomeTest <Integer> mRef = new MyClass<Integer>()::myGenMeth;
mRef.test(1, 2);
Supplier<Boolean> p = new ArrayList<>()::isEmpty;
p.get();
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