Windows批处理文件，在标记之间找到一个字符串

Question

i need to search within a file the first occurrence of a string.

I have this php file:

<?php

#---------------------------------------------------------------------------------------
#
#
#  Gpl V2 and further license updates applies to this code
#
#  2015/05/21
#
#-------------------------------------------------------------------------------

error_reporting(0);

$version = '1.0 Alpha';

//some code
echo "\r\n===== ".$argv[0]." ".$version.": Select a channel =====: ";

I need to find this value 1.0 Alpha . In a bat file i have write this code.

for /f "tokens=*" %%x in ('findstr "$version" %~1') do (
set str=%%x
)

But he found all second string: echo "\\r\\n===== ".$argv[0]." ".$version.": Select a channel =====: ";

Solutions?

One last thing, the script could change from $version = '1.0 Alpha'; to $version = "1.0 Alpha";

The quotes may change.

Answer 1

You need to exit the loop after finding the first occurrence of the string. Try this:

for /f "tokens=*" %%x in ('findstr "$version" %~1') do (
   set str=%%x
   goto :EndFor
)
:EndFor

set str=%str:"='% 
for /f "tokens=2 delims='" %%x in ('echo(%str%') do set str=%%x
echo(str=%str%
pause

Answer 2

This can be done in a single step, letting the FOR /F loop parse out the actual version string.

The odd syntax specifies ' and " as token delimiters, and looks for the 2nd token.

@echo off
setlocal
for /f tokens^=2^ delims^='^" %%V in ('findstr $version "%~1"') do (
  set "version=%%V
  goto :break
)
:break
echo version=%version%