[英]How to convert a sequence variable into a matrix in Scala
This should be easy, but I'm stuck. 这应该很容易,但是我被卡住了。 I'm trying to convert a
Seq[Seq[Double]]
type into a Breeze DenseMatrix
. 我正在尝试将
Seq[Seq[Double]]
类型转换为Breeze DenseMatrix
。 (all nested Seq[Double]'s have the same number of elements.) (所有嵌套的Seq [Double]具有相同数量的元素。)
Converting a single sequence to a DenseVector
is pretty easy: 将单个序列转换为
DenseVector
非常简单:
val sss=Seq(2.3,3.4,2.0,1.0)
val bbb=DenseVector(sss:_*)
Is there any similar approach to convert a Seq[Seq[Double]]
type to a DenseMatrix
? 是否有类似的方法将
Seq[Seq[Double]]
类型转换为DenseMatrix
? For example: 例如:
val sss=Seq(2.3,3.4,2.0,1.0)
val sssM=Seq(sss,sss,sss)
val bbb=DenseVector(sss:_*)
//val bbm= DenseMatrix(sssM:_*:??) //????
I noticed that the same approach works fine: 我注意到相同的方法可以正常工作:
val sss=Seq(2.3,3.4,2.0,1.0)
val sssM=Seq(sss,sss,sss)
val bbb=DenseVector(sss:_*)
val bbm= DenseMatrix(sssM:_*)
Initially I had thought that we need to expand each nested sequence as well. 最初,我以为我们也需要扩展每个嵌套序列。 But as stated by Rex Kerr, in a comment below, the Breeze library automatically takes care of that.
但是正如Rex Kerr所述,在下面的评论中,Breeze库自动解决了这一问题。
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