[英]How to get boolean or of two numpy masks with Python
Given two numpy array masks, created with the 3rd and 4th columns of data of 7 columns total: 给定两个numpy数组掩码,分别使用第7列的第3列和第4列数据创建:
exp_mask = np.repeat(data[:,2]>7., data.shape[1])
loggf_mask = np.repeat(data[:,3]<-7., data.shape[1])
How can I mask data which are masked by either exp_mask
or loggf_mask
? 如何屏蔽被
exp_mask
或loggf_mask
屏蔽的数据?
The logic of what I am trying to describe is: 我要描述的逻辑是:
mask = exp_mask or loggf_mask
我相信您正在寻找按位或,即|。
您可以使用np.any()评估布尔值或掩码:
mask = np.any([exp_mask,loggf_mask],axis=0)
You can use either bitwise_or
, which also has the |
您可以使用
bitwise_or
,也可以使用|
shorthand, or logical_or
. 简写形式,或
logical_or
。 Both will work since your array will be of type bool
: 两者都可以使用,因为您的数组将为
bool
类型:
mask = exp_mask | loggf_mask
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