使用正则表达式删除单个字符后跟一个O

Question

i need to match if a middle name is composed of the following characters, “JO”, the O will be deleted, leaving behind the “J”. My regex is standardName.replaceAll("(?<=[AZ])[O]*", "") . This is working but its replacing other strings too. For eg if i pass SOO BOO i am getting as SB only if i get a single character followed by O like above O should be replaced else not. Any suggestions?

Answer 1

You can use word boundary on both sides:

standardName = standardName.replaceAll("(?<=\\b[A-Z])O\\b", "");

RegEx Demo

Answer 2

standardName.replaceAll("(?<=\\s[A-Z]|^[A-Z])[A-Z])[O]\\b", "")

This should do it for you. \\b is a word boundary which will not allow a letter after first O .

or

standardName.replaceAll("(?<=\\s[A-Z]|^[A-Z])O(?=\\s|$)", "")

Answer 3

You may try this,

standardName.replaceAll("(?<=\\s[A-Z])O(?!\\S)", "");

Following negative lookahead asserts that the O must not be followed by a non-space character.

or

standardName.replaceAll("\\s([A-Z])O\\s", "$1");