[英]Replacing Character using Regular Expression in java
I have a String
where a substring with third bracket can contain like that 我有一个
String
,其中带有第三括号的子字符串可以包含这样的字符串
String str = "merSampleFactoryList[0].tfSendDate.fields[0].durationField.supported";
I want to replace all [0]
, [1]
, [2]
...... with " []
" . 我要替换所有
[0]
[1]
[2]
......以“ []
I know i can do it using regular expression but don't know how to do that. 我知道我可以使用正则表达式来做,但是不知道该怎么做。
You can use String::replaceAll with regex \\[.*?\\]
: 您可以将String :: replaceAll与正则表达式
\\[.*?\\]
:
str = str.replaceAll("\\[.*?\\]", "[]")
Output 输出量
merSampleFactoryList[].tfSendDate.fields[].durationField.supported
Note 注意
In case you want to replace only the bracket which contains integers then you can use \\[\\d+\\]
instead. 如果只想替换包含整数的括号,则可以改用
\\[\\d+\\]
。
Or like @Dukeling mention in comment you can use \\[[^]]*\\]
instead of \\[.*?\\]
或像评论中提到的@Dukeling一样,您可以使用
\\[[^]]*\\]
代替\\[.*?\\]
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