在Java中使用正则表达式替换字符组

Question

I have a string like this:

<b.*?n.*? .*?a.*?n.*? .*?e.*?&nbsp;.*? .*? .*? .e.*?t.*?e.*?   .*?   .*? .*? .*?<.r>.*? .*?e.*? .*? .*? .*?l.*?e .*?b.*?e.*?n.*?b.*? .*?  .*?a.*?p.*?t.*? .*?l.*? .*? .*? .*? .*? ..b.*? .*? .*?s.*?   .*?s.*?   .*?>.*? .*?es.*? .*?n.*?t.*?r.*? .*? .*? .*? .n.*?b.*? .*? .*? .*? .*? .*?e.*? .*? .*? .*? .*?t.*?n.*? .*? .*? .*? .*?n.s.. .*?a. .*? <.*?e.e.*? comp.*? .*?<.*? .*?r.*?el.*?&.*?b.*? .*? .*?y.*? ..e.*? .. .*? .*? .*? .*? .*?u.t.*?m..o.*?b.*?r.*?e.*?n.*?o.. .*? .*?s. .*?e.*?o.. .*?r.*?r.*?&.*?b.*? ..b>.*?o.*?s.*? .*?r.*? .*? .*?a..i.*? .*? .*? .*?e.*?in.*? .*? .*? .*? .*? .*? .*? ..b.*? .*? .*? .*?r..i.*?c.*? .*? .*?o.*?<..>.*?

Sorry but the * is removed from the text above.

I want to be able to replace consecutive appearance of .*? into a single .*? . I tried

res = tmp.replaceAll("(\\s\\.\\*\\?)(\\1{2,})","\\s\\.\\*\\?");

but it did not work. Is there something wrong in my code?

Answer 1

I would suggest you to use loop and replace it. something like follow

        String pattern= "(.\*\?\s.\*\?)";
        if(YOURSTRING.matches(pattern)){
            // replace two .*? to one 
        }
        else{ 
            // break your loop   
            }

this is not a complete solution. But some basic idea

Answer 2

You could try this:

str.replaceAll("\\p{Blank}+", "").replaceAll("[\\.\\*\\?]+", ".*?");

Example:

String str = "abcabcddabceeabcabc";
str = str.replaceAll("[abc]+", "abc");
System.out.println("str = " + str);

And the result:

str = abcddabceeabc

Answer 3

You can use

(\s*)(?:\s*\.\*\?){2,}

And replace with $1.*? . The Group 1 backreference $1 will keep the initial whitespace before the first .*? .

The regex matches:

• (\\s*) - Group 1: zero or more whitespace symbols
• (?:\\s*\\.\\*\\?){2,} - two or more sequences of:
  • \\s* - zero or more whitespace symbols
  • \\. - a literal dot
  • \\* - a literal asterisk
  • \\? - a literal ? symbol

See the regex demo .

Sample code:

String p = "(\\s*)(?:\\s*\\.\\*\\?){2,}"; 
String str = "<b.*?n.*? .*?a.*?n.*? .*?e.*? \\.*? .*? .*? .e.*?t.*?e.*?   .*?   .*? .*? .*?<.r>.*? .*?e.*? .*? .*? .*?l.*?e .*?b.*?e.*?n.*?b.*? .*?  .*?a.*?p.*?t.*? .*?l.*? .*? .*? .*? .*? ..b.*? .*? .*?s.*?   .*?s.*?   .*?>.*? .*?es.*? .*?n.*?t.*?r.*? .*? .*? .*? .n.*?b.*? .*? .*? .*? .*? .*?e.*? .*? .*? .*? .*?t.*?n.*? .*? .*? .*? .*?n.s.. .*?a. .*? <.*?e.e.*? comp.*? .*?<.*? .*?r.*?el.*?&.*?b.*? .*? .*?y.*? ..e.*? .. .*? .*? .*? .*? .*?u.t.*?m..o.*?b.*?r.*?e.*?n.*?o.. .*? .*?s. .*?e.*?o.. .*?r.*?r.*?&.*?b.*? ..b>.*?o.*?s.*? .*?r.*? .*? .*?a..i.*? .*? .*? .*?e.*?in.*? .*? .*? .*? .*? .*? .*? ..b.*? .*? .*? .*?r..i.*?c.*? .*? .*?o.*?<..>.*?"; 
String subst = "$1.*?"; 
System.out.println(str.replaceAll(p, subst));

See IDEONE demo