[英]Non greedy regex is not working as expected
I need to take certain part from the string with regex non greedy approach. 我需要使用正则表达式非贪婪方法从字符串中获取某些内容。 I am manipulating following string :
我正在操纵以下字符串:
<a href="/guidance/">Hi</a> </li><li > <a href="/news/institutional/2012/05/000001asdf">Thanks</a>
from which I need to get : 从中我需要得到:
<a href="/news/institutional/2012/05/000001asdf">Thanks</a>
I've been trying with following regex : 我一直在尝试以下正则表达式:
<a.*?news/.*?/(\d{1,4}\/[01]?\d)?.*?</a>
but it gets all string instead of part of string mentioned above.As far as I understand .*?
但是它得到了所有字符串而不是上面提到的一部分字符串。据我了解
.*?
capture shortest match but it's not working as expected. 捕获最短的匹配,但未按预期运行。
This [^>]
is a negative character class, any character except angle 此
[^>]
是否定字符类, 除 angle 以外的任何字符
brace. 支撑。 This stops a non-greedy
.*?
这会停止非贪婪的
.*?
from matching the end of the tag 从匹配标签的结尾
(turning it semi-greedy) when it can't find the specific news
anchor. (将其设为半贪婪状态),当它找不到特定的
news
主播时。
# @"(?s)<a[^>]*?news/[^>/]*?/(\d{1,4}(?:/\d+)*)?[^>]*?>.*?</a>"
(?s) # Modifier, Dot-Matches any character
<a # Open 'a' tag
[^>]*? # Any non '>' character
news/ # Need 'news/'
[^>/]*? # Any non '>' or '/' character
/ # Need '/'
( # (1 start), Optional Date ?
\d{1,4} # 1-4 digit year
(?: / \d+ )* # month / day, etc ..
)? # (1 end)
[^>]*? # Any non '>' character
> # End Open '>' tag
.*? # Anything
</a> # Close 'a' tag
C# example: C#示例:
string news = @"
<a href=""/guidance/"">Hi</a> </li><li > <a href=""/news/institutional/2012/05/000001asdf"">Thanks</a>
<a href=""/rintime/"">Hi</a> <a href=""/news/google/asdf"">GOOGLE</a>
";
Regex RxNews = new Regex(@"(?s)<a[^>]*?news/[^>/]*?/(\d{1,4}(?:/\d+)*)?[^>]*?>.*?</a>" );
Match _mNews = RxNews.Match( news );
while (_mNews.Success)
{
Console.WriteLine("Found: {0}\r\nGroup 1 = {1}\r\n", _mNews.Groups[0].Value, _mNews.Groups[1].Value);
_mNews = _mNews.NextMatch();
}
Output: 输出:
Found: <a href="/news/institutional/2012/05/000001asdf">Thanks</a>
Group 1 = 2012/05/000001
Found: <a href="/news/google/asdf">GOOGLE</a>
Group 1 =
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.