在快速的iOS 8中，当单击一个单元格时，如何获取它以打开另一个视图控制器？

Question

I'm fairly new to swift programming, and been trying for hours . Any help is well appreciated.

Answer 1

Just override: didSelectRowAtIndexPath

override func tableView(tableView: UITableView!, didSelectRowAtIndexPath path: NSIndexPath!) {
    let secondViewController = 
        self.storyboard.instantiateViewControllerWithIdentifier("SecondViewController")
        as SecondViewController
    self.navigationController.pushViewController(secondViewController, animated: true)
}

Answer 2

To expand on @Epic Defeater's comment, if your table view controller and the destination view controller is in the same storyboard, control-drag from the table cell to the destination view controller. This is a segue, and it does what @Klevison Matias's code does, but with less involvement from you.

The segue needs a unique identifier, and in your table view controller, you must implement prepareForSegue:sender: .

Answer 3

You need to create an instance of the View Controller that you want to open and then transition to that view controller - presumably, by 'pushing' that View Controller onto the navigation stack (navigation controller).

For example...

let nextViewController: MyViewController = MyViewController()
self.navigationController.pushViewController(nextViewController, animated:true)

Answer 4

只需将单元格中的segue添加到要与其连接的视图控制器即可。