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如何将此查询转换为SQL Server 2000语法

[英]How to convert this query to SQL Server 2000 syntax

I am running this query to SQL Server 2008+ but it doesn't work on SQL Server 2000. and i need this to execute. 我正在运行此查询到SQL Server 2008+但它不适用于SQL Server 2000.我需要执行此操作。

WITH CTE AS ( 
    SELECT
        custnum,
        custname,
        RN = ROW_NUMBER() OVER( PARTITION BY custnum, custname ORDER BY custnum )
    FROM
        cust
)
SELECT
    *
FROM
    CTE
WHERE RN > 1

thank you so much for your help! 非常感谢你的帮助!

See if this works 看看这是否有效

select custnum,custname from
(
select (select count(*) from cust as t1 where t1.custnum<=t2.custnum) as sno,
 custnum,custname from cust as t2
) as t
where sno>1

Prior to SQL Server 2005, this problem domain was solved with ordered inserts into a #temp table with an IDENTITY column to generate the sequence number. 在SQL Server 2005之前,通过对带有IDENTITY列的#temp表中的有序插入来解决此问题域,以生成序列号。 This would solve RANK() and ROW_NUMBER() requirements. 这将解决RANK()ROW_NUMBER()要求。

Eg: 例如:

    -- Create empty temp table
    SELECT custnum, custname, IDENTITY(INT, 1, 1) as RN
    INTO #cust
    FROM cust
    WHERE 0 = 1

    -- Populate with ORDER BY, to generate ascending RN
    INSERT INTO #cust
        (custnum, custname)
    SELECT
        custnum, custname
    FROM 
        cust
    ORDER BY
        custnum, custname

At that point, you can query MIN() for each custnum/custname grouping and use that as you'd use the CTE. 此时,您可以查询每个custnum / custname分组的MIN() ,并在使用CTE时使用它。

However ... is ROW_NUMBER() really what you want here ? 但是...... ROW_NUMBER()真的是你想要的吗? Seems like you'd want RANK() , not ROW_NUMBER() . 好像你想要RANK() ,而不是ROW_NUMBER()

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