如何將此查詢轉換為SQL Server 2000語法

Question

我正在運行此查詢到SQL Server 2008+但它不適用於SQL Server 2000.我需要執行此操作。

WITH CTE AS ( 
    SELECT
        custnum,
        custname,
        RN = ROW_NUMBER() OVER( PARTITION BY custnum, custname ORDER BY custnum )
    FROM
        cust
)
SELECT
    *
FROM
    CTE
WHERE RN > 1

非常感謝你的幫助！

Answer 1

看看這是否有效

select custnum,custname from
(
select (select count(*) from cust as t1 where t1.custnum<=t2.custnum) as sno,
 custnum,custname from cust as t2
) as t
where sno>1

Answer 2

在SQL Server 2005之前，通過對帶有IDENTITY列的#temp表中的有序插入來解決此問題域，以生成序列號。 這將解決RANK()和ROW_NUMBER()要求。

例如：

    -- Create empty temp table
    SELECT custnum, custname, IDENTITY(INT, 1, 1) as RN
    INTO #cust
    FROM cust
    WHERE 0 = 1

    -- Populate with ORDER BY, to generate ascending RN
    INSERT INTO #cust
        (custnum, custname)
    SELECT
        custnum, custname
    FROM 
        cust
    ORDER BY
        custnum, custname

此時，您可以查詢每個custnum / custname分組的MIN() ，並在使用CTE時使用它。

但是...... ROW_NUMBER()真的是你想要的嗎？ 好像你想要RANK() ，而不是ROW_NUMBER() 。