[英]rank query in sql server 2000
我正在嘗試創建一個查詢,該查詢將帶來一個JOB_ID的最后狀態,這在SQL Server 2008中使用基於分區的排名功能很簡單,但是在SQL Server 2000上,此功能不可用。 我已經設法通過Job_ID升序和DATETIME降序將作業歷史記錄按順序放在臨時表中( # JOB_HISTORY-請注意pk_ID是使用以下臨時表生成的: IDENTITY(int, 1,1)
),但這是我卡住的部分,我不知道如何對這張表中的記錄進行排名。
SELECT
h1.pk_ID,
h1.Job_ID,
h1.Status,
h1.DATETIME
FROM #JOB_HISTORY h1
ORDER BY h1.pk_ID ASC;
#JOB_HISTORY結果:
pk_ID, Job_ID, STATUS, DATETIME
1 1234 Succeded. 2015-03-30 12:10
2 1234 Failed. 2015-03-30 01:00
3 1234 Failed. 2015-03-28 01:00
4 5678 Failed. 2015-04-02 04:00
5 5678 Succeded. 2015-04-01 04:00
6 5678 Succeded. 2015-03-31 04:00
期望的輸出:
Job_ID STATUS DATETIME
1234 Succeded. 2015-03-30 12:10
5678 Failed. 2015-04-02 04:00
SQL Server可以按任意順序自由插入記錄,因此我不相信IDENTITY(int, 1,1)
總是為您提供正確的順序。 它可能在某些版本中有效。
您可以在內部加入一個子查詢,在其中獲得最大日期時間(或最小pk_ID)以獲取第一行/最后一行。 這是一個獲得SQL Server 2000中每個作業的最后結果的工作示例:
use msdb;
select
sysjobhistory.job_id as job_id
-- https://msdn.microsoft.com/en-us/library/ms174997.aspx
, case sysjobhistory.run_status
when 0 then 'Failed'
when 1 then 'Succeeded'
when 2 then 'Retry'
when 3 then 'Canceled'
else cast(sysjobhistory.run_status as varchar(10))
end as run_status
, jobLastHistory.lastDateTime as execution_time
FROM dbo.sysjobhistory as sysjobhistory
inner join (
--last datetime for each job_id
SELECT
history.job_id
, max( --newest
CONVERT(DATETIME, STUFF(STUFF(STUFF( --yyyymmddhhmiss --> datetime
cast(history.run_date as varchar(8))--yyyymmdd
+right('000000'+cast(history.run_time as varchar(8)),6) --hhmiss
,13,0,':'),11,0,':'),9,0,' '))
) AS lastDateTime
FROM dbo.sysjobhistory as history
where history.step_id = 0 --job outcome
group by
history.job_id
) as jobLastHistory
on jobLastHistory.job_id
= sysjobhistory.job_id --same job
and convert(varchar(8),jobLastHistory.lastDateTime,112)
= sysjobhistory.run_date --latest date (yyyymmdd)
and replace(convert(varchar(8),jobLastHistory.lastDateTime,108),':','')
= sysjobhistory.run_time --latest time (hhmiss)
where sysjobhistory.step_id = 0 --job outcome
;
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