使用PHP旋转然后裁剪图像

Question

I'm trying to crop my image, but when I do it shows up as the right size, but all black. I've tried at least a dozen different scripts but I can't seem to get any of them to work :(

Oh and the rotation script works fine, and all of the echos are just for testing and will be removed :D

<?php

$staffID        =   $_POST['u'];
$actCode        =   $_POST['a'];
$tempAvatar     =   $_POST['tempAvatar'];
$x1             =   $_POST['x'];
$y1             =   $_POST['y'];
$wH             =   $_POST['w'];
$scale          =   $_POST['scale'];
$angle          =   $_POST['angle'];
$destFolder     =   "../../../avatars/";
$imagePath      =   "tempAvatars/".$tempAvatar.".jpg";
$imagePathRot   =   "tempAvatars/".$tempAvatar."ROTATED.jpg";
$imagePathCropped=  "tempAvatars/".$tempAvatar."CROPPED.jpg";

echo 'X1: '.$x1.'<br>Y1: '.$y1.'<br>Width/Height: '.$wH.'<br>Angle: '.$angle;
if ($angle != 0) {

    $source = imagecreatefromjpeg($imagePath) or notfound();
    $rotate = imagerotate($source,$angle,0);
    imagejpeg($rotate, $imagePathRot);

    $imagePath  =   $imagePathRot;
}

echo '<br>X2: '.$x2.'<br>Y2: '.$y2;

$targ_w = 300;
$jpeg_quality = 90;

$img_r = imagecreatefromjpeg($imagePath);
$dst_r = ImageCreateTrueColor( $targ_w, $targ_w );

imagecopyresampled($dst_r,$img_r,0,0,$_POST['x'],$_POST['y'],
    $targ_w,$targ_h,$_POST['w'],$_POST['w']);

imagejpeg($dst_r, $imagePathCropped, $jpeg_quality);



echo '<br><img src="'.$imagePathCropped.'">';


?>

Answer 1

Your problem is that $targ_h is not defined, therefore you are copying 0 pixel "rows" from the source image. It's in the correct size because it's decided by ImageCreateTrueColor and of course initialized to black. The correct call according to the rest of your code should be:

imagecopyresampled($dst_r,$img_r,0,0,$_POST['x'],$_POST['y'],
    $targ_w,$targ_w,$_POST['w'],$_POST['w']);