回显HTML和PHP给出语法错误
[英]echo html and php giving syntax error
问题描述
There are similar questions on StackOverflow but I'm still having trouble fixing my problem. 
在StackOverflow上也有类似的问题，但是我仍然无法解决问题。 This is what I have 这就是我所拥有的
<video class="video-js vjs-default-skin" width="100%" poster="sqqsdqd.jpg" data-setup='{"controls":true, "autoplay": true, "preload": "auto"}'><source src="$media['data']['videos']['standard_resolution']['url']" type="video/mp4" /></video>
I need to echo it using php but whenever I try I'm getting a syntax error. 我需要使用php回显它，但是每当我尝试时都会遇到语法错误。 This code: 这段代码：
echo '<div class="pic"><img src=" ' . $media['data']['images']['standard_resolution']['url'] . '"></div>';
is working fine but I can't figure out how to do it for the video one, help is appreciated. 工作正常，但我不知道如何为视频做一个，感谢您的帮助。 Thank you. 谢谢。
Edit: Sorry my actual code is like this 编辑：对不起，我的实际代码是这样的
<?php if ($media['data']['type'] == 'image') { echo '<div class="pic"><img src=" ' . $media['data']['images']['standard_resolution']['url'] . '"></div>'; } else { echo '<video class="video-js vjs-default-skin" width="100%" poster="httjpg" data-setup='{"controls":true, "autoplay": true, "preload": "auto"}'> <source src=" '.$media['data']['videos']['standard_resolution']['url'].'" type="video/mp4" /></video>'; } ?>
2 个解决方案
解决方案1
1 已采纳 2015-08-08 04:09:32
Just try this, 试试这个
<?php
echo 'yourstuff';
?>
<video class="video-js vjs-default-skin" width="100%" poster="sqqsdqd.jpg" data-setup='{"controls":true, "autoplay": true, "preload": "auto"}'><source src="<?php echo $media['data']['videos']['standard_resolution']['url'] ?>" type="video/mp4" /></video>
<?php
echo 'yourstuff';
?>
update: 更新：
<?php
if ($media['data']['type'] == 'image') {
echo '<div class="pic"><img src=" ' . $media['data']['images']['standard_resolution']['url'] . '"></div>';
} else {
?>
<video class="video-js vjs-default-skin" width="100%" poster="sqqsdqd.jpg" data-setup='{"controls":true, "autoplay": true, "preload": "auto"}'><source src="<?php echo $media['data']['videos']['standard_resolution']['url'] ?>" type="video/mp4" /></video>
<?php
}
?>
I hope this will help to acheive 我希望这将有助于实现
解决方案2
0 2015-08-08 04:45:05
This issue comes because you have bad quoting style on this line 出现此问题的原因是您在此行上的引用样式不好
'<video class="video-js vjs-default-skin" width="100%" poster="httjpg" data-setup='
See the apos ( single quotes ), there are several ways around this. 参见撇号（单引号），有几种解决方法。 The previous answer is one of them. 先前的答案就是其中之一。 Here is another 这是另一个
<?php
if ($media['data']['type'] == 'image') {
echo '<div class="pic"><img src=" ' . $media['data']['images']['standard_resolution']['url'] . '"></div>';
} else {
echo <<<HTML
<video class="video-js vjs-default-skin" width="100%" poster="httjpg" data-setup='{"controls":true, "autoplay": true, "preload": "auto"}'> <source src="{$media['data']['videos']['standard_resolution']['url']}" type="video/mp4" /></video>
HTML;
}
?>
Note that the closing HTML; 注意关闭HTML; must be on it's own line with no space before or after it. 必须在它自己的行之前或之后没有空格。 It's called a HEREDOC 叫做HEREDOC
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