字符串python 3中最常见的元音

Question

I have created the program for the most frequent vowel in a string but the problem that i am having is i want to print only one letter for the most frequent vowel, not both. My code is displayed below:

from collections import Counter
words = input("Enter a line of text: ")
vowel = "aeiouAEIOU"
x = Counter(c for c in words.upper() if c in vowel)

most = {k: x[k] for k in x if x[k] == max(x.values())}

for i in most:
    vowel = i
    y = most[i]
    print("The most occuring vowel is:",vowel, "with",y,"occurences")

if vowel != words:
    print("No vowels found in user input")

When i run the code for example i enter "aa ee" it will print:

The most occuring vowel is: A with 2 occurences
The most occuring vowel is: E with 2 occurrences

I only want it to print either A or E?

Answer 1

Why you don't simply use Counter.most_common() which is most appropriate way for doing this job?

words = input("Enter a line of text: ")
vowels = set("aeiouAEIOU")
x = Counter(c for c in words if c in vowels)

print x.most_common()

Also note that you don't need to use word.upper since you have all the vowels type.And as said in comment you can use set for preserving the vowels which its membership checking complexity is O(1).