goog.Timer.callOnce不符合形式参数：谷歌关闭

Question

I get the error for formal parameter not matching when using goog.Timer.callOnce even when I think I have declared everything correctly.

goog.Timer.callOnce(/** @type {function} */ this.doSomething,0,this); 

the method definition looks like

/**
* @param {!goog.events.Event} e
*/
model.someModel.prototype.doSomething = function(e){
}

The error looks like

ERROR - actual parameter 1 of goog.Timer.callOnce does not match formal parameter
==> default: [ERROR] found   : function (this:model.someModel, goog.events.Event): undefined
==> default: [ERROR] required: (function (this:model.someModel): ?|null|{handleEvent: function (): ?})
==> default: [ERROR] goog.Timer.callOnce(/** @type {function} */doSomething,0,this);

I also tried typecasting /** @type {function()} */ but even this didnt work

Answer 1

The compiler is expecting a function that takes no arguments (because goog.Timer isn't going to pass any arguments) but you're passing a function that expects one argument. Either change the function so that it doesn't take an argument, or make the argument optional:

/**
 * @param {!goog.events.Event=} opt_e
 */
model.someModel.prototype.doSomething = function(opt_e) {
  if (opt_e) {
    ...
  } else {
    ...
  }
}