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如何修剪此Swift字符串?

[英]How can I trim this Swift string?

I have a bunch of addresses as strings that are in the following example format: 我有一堆地址作为字符串,格式如下:

8 Smith st, Sydney, New South Wales, Australia 8 Smith st,悉尼,新南威尔士州,澳大利亚

However, I'd like to trim them down to the following format: 但是,我想将它们缩小为以下格式:

8 Smith st, Sydney 悉尼史密斯街8号

How can I acheive this? 我该如何实现? Thanks. 谢谢。

here you can trim White space using this 在这里您可以使用此功能修剪空白

var myString = "    Let's trim the whitespace    "
var newString = myString.stringByTrimmingCharactersInSet(NSCharacterSet.whitespaceCharacterSet())
//Returns "Let's trim the whitespace"

in your Case, first you have to convert it in Array and then convert it as a string as given in below Example 在您的案例中,首先必须将其转换为数组,然后将其转换为字符串,如下面的示例所示

var myString = "Berlin, Paris, New York, San Francisco"
var myArray = myString.componentsSeparatedByString(",")
//Returns an array with the following values:  ["Berlin", " Paris", " New York", " San Francisco"]

For More you can learn From here 要了解更多,您可以从这里学习

in your Case, first you have to convert it in Array and then convert it as a string as given in below Example 在您的案例中,首先必须将其转换为数组,然后将其转换为字符串,如下面的示例所示

var myString = "8 Smith st, Sydney, New South Wales, Australia"
var myArray = myString.componentsSeparatedByString(",")
//Returns an array with the following values:  ["8 Smith st", " Sydney", " New South Wales", " Australia"]

if myArray.count > 1
{
    println(myArray[0]) //8 Smith st
    println(myArray[1]) //Sydney
}

Truncate string/text to Specific Length 将字符串/文本截断为特定长度

If you have entered block of sentence/text and you want to save only specified length out of it text. 如果您输入了句子/文本块,并且您只想在文本中保存指定的长度。 Add the following extension to Class 将以下扩展添加到Class

extension String {

   func trunc(_ length: Int) -> String {
    if self.characters.count > length {
        return self.substring(to: self.characters.index(self.startIndex, offsetBy: length))
    } else {
        return self
    }
  }
}

Use 采用

var str = "Lorem Ipsum is simply dummy text of the printing and typesetting industry."
//str is length 74
print(str)
//O/P:  Lorem Ipsum is simply dummy text of the printing and typesetting industry.

str = str.trunc(40)
print(str)
//O/P: Lorem Ipsum is simply dummy text of the 

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