[英]How can I trim this Swift string?
我有一堆地址作為字符串,格式如下:
8 Smith st,悉尼,新南威爾士州,澳大利亞
但是,我想將它們縮小為以下格式:
悉尼史密斯街8號
我該如何實現? 謝謝。
var myString = " Let's trim the whitespace "
var newString = myString.stringByTrimmingCharactersInSet(NSCharacterSet.whitespaceCharacterSet())
//Returns "Let's trim the whitespace"
在您的案例中,首先必須將其轉換為數組,然后將其轉換為字符串,如下面的示例所示
var myString = "Berlin, Paris, New York, San Francisco"
var myArray = myString.componentsSeparatedByString(",")
//Returns an array with the following values: ["Berlin", " Paris", " New York", " San Francisco"]
在您的案例中,首先必須將其轉換為數組,然后將其轉換為字符串,如下面的示例所示
var myString = "8 Smith st, Sydney, New South Wales, Australia"
var myArray = myString.componentsSeparatedByString(",")
//Returns an array with the following values: ["8 Smith st", " Sydney", " New South Wales", " Australia"]
if myArray.count > 1
{
println(myArray[0]) //8 Smith st
println(myArray[1]) //Sydney
}
將字符串/文本截斷為特定長度
如果您輸入了句子/文本塊,並且您只想在文本中保存指定的長度。 將以下擴展添加到Class
extension String {
func trunc(_ length: Int) -> String {
if self.characters.count > length {
return self.substring(to: self.characters.index(self.startIndex, offsetBy: length))
} else {
return self
}
}
}
采用
var str = "Lorem Ipsum is simply dummy text of the printing and typesetting industry."
//str is length 74
print(str)
//O/P: Lorem Ipsum is simply dummy text of the printing and typesetting industry.
str = str.trunc(40)
print(str)
//O/P: Lorem Ipsum is simply dummy text of the
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